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MatroZZZ [7]
3 years ago
8

There are two types of circuits we can make and they are ...

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
4 0
They are

parallel circuit and series circuit
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Potassium and fluorine are both halogens?​
andreev551 [17]

Answer:

false, Potassium and fluorine are not halogens.

only fluorine here is halogen.

potassium is an alkali earth metal it doesn't comes under category of halogens, but fluorine

is a non metal which comes under halogen family.

7 0
2 years ago
When the temperature of a sample of neon gas increases, what else increases? Distance between the atoms Kinetic energy of the at
Allushta [10]

Answer: Kinetic Energy of the atoms also increases.

Explanation: We are given that the temperature of the gas increases.

Relation between kinetic energy and temperature follows:

K.E._({avg})=\frac{3RT}{2N_A}

where, K = Average Kinetic energy

R = Gas constant

T = Temperature

N_A = Avogadro's number

As seen from the relation above, the Kinetic energy of the gas is directly proportional to the temperature, hence as the temperature increases, kinetic energy of the atom also increases.

4 0
3 years ago
Under the same conditions of solar radiation, compared with oceans the land will warm_________
aksik [14]
Land will warm faster/quicker
7 0
3 years ago
Sorry if it is blurry
Zina [86]
I really cant read it sorry i tried
7 0
3 years ago
Read 2 more answers
Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m
Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>;  that is

molarity = moles of solute ÷ liters of solution

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

Our first step is to calculate the moles of urea in 100 grams of the solution,

using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is

60.06 g/mol ÷ 37.2 g = 0.619 mol

Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.

1.032 g/mL ÷ 100 g = 96.9 mL

This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.

0.619 mol/96.9 mL × 1000 mL= 6.39 M

Therefore, the molarity of the solution is 6.39 M.

4 0
3 years ago
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