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3 years ago

7

Which statement describes J.J. Thomson’s plum-pudding model of the atom?

1 answer:

ra1l [238]3 years ago

4 0

Option C: the electrons are embedded in a positive sphere.

As we know that was a wrong model and nowadays the electrons are considered to be around the nucleus, in regions called orbitals.

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A solution has a [oh−] of 1 x 10−12. what is the poh of this solution? 2 7 10 12

Colt1911 [192]

POH = - log [ OH-]

pOH = - log [ 1 x 10⁻¹²]

pOH = 12

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2 years ago

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All of the following are possible sources of error in a scientific investigation except for

Dimas [21]

Answer: Common sources of error include instrumental, environmental, procedural, and human. All of these errors can be either random or systematic depending on how they affect the results. Make sure you have your problem, hypothesis, evidence, analyze the data, ask yourself if the evidence supports ur hypothesis, draw conclusions, and communicate your results!

Explanation:

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3 years ago

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Can someone help me? It needs to have a diagram that has arrows.

daser333 [38]

Answer: The enthalpy change for formation of butane is -125 kJ/mol

Explanation:

The balanced chemical reaction is,

$C_4H_{10}(g)+\frac{13}{2}O_2(g)\rightarrow 4CO_2(g)+5H_2O(l)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f{products}]-[n\times H_f{reactants}]$

Putting the values we get :

$\Delta H=[4\times H_f_{CO_2}+5\times H_f_{H_2O}]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times H_f_{O_2}]$

$-2877=[(4\times -393)+(5\times -286)]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times 0]$

$H_f_{C_4H_{10}=-125kJ/mol$

Thus enthalpy change for formation of butane is -125 kJ/mol

5 0

3 years ago

If a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay, what will be the new element?

Charra [1.4K]

Answer:

The new element will be thorium-226 (²²⁶Th).

Explanation:

The beta decay is given by:

$^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y + \beta^{-} + \bar{\nu_{e}}$

Where:

A: is the mass number

Z: is the number of protons

β⁻: is a beta particle = electron

$\bar{\nu_{e}}$ : is an antineutrino

The neutral atom has 88 electrons, so:

$e^{-} = 88 = Z$

Hence the element is radium (Ra), it has A = 226.

If Ra undergoes 2 rounds of beta minus decay, we have:

$^{226}_{88}Ra \rightarrow ^{226}_{89}Ac + \beta^{-} + \bar{\nu_{e}}$

$^{226}_{89}Ac \rightarrow ^{226}_{90}Th + \beta^{-} + \bar{\nu_{e}}$

Therefore, if a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay the new element will be thorium-226 (²²⁶Th).

I hope it helps you!

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2 years ago

Some animals hunt by _______ or sneaking up on their prey. It a nine letter word and there a m in the second place

guajiro [1.7K]

Answer:

Some animals hunt by <em>Camouflage</em> or sneaking up on their prey.

5 0

1 year ago