Answer:
Ea=5.29 × 10⁴ J/mol
Explanation:
In going from 25 °C (298 K) to 35 °C (308 K), the rate of the reaction doubles. Since the rate of the reaction depends on the rate constant (k), this implies that the rate constant doubles. We can find the activation energy (Ea) using the two-point form of the Arrhenius equation.

Answer:

Explanation:
Hello!
In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:

Thus, we first need to compute the molality of each solute, as shown below:

Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:

It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.
Best regards!
Well, every location is located in two hemispheres. New York is in the north western hemisphere. North of the equator and west of the prime meridian
The pH of a solution is a measure of the acidity of a solution and is logarithmically related to the hydrogen ion concentration. It is expressed as:
pH = -log [H+]
We use this to determine the amount of H+ needed to adjust the pH to the desired value.
pH1 = 7.2 = -log [H+]
[H+] = 6.31x10^-8
pH2 = 8.2 = -log [H+]
[H+] = 6.31x10^-9
[H+] to be added = 6.31x10^-8 - 6.31x10^-9 = 5.68x10^-8 M
She should add an acidic solution with concentration 5.68x10^-8 M. Hope this helps.
Molar mass
NH3 = 17 g/mol
N2 = 28 g/mol
4 NH3 + 6 NO = 5 N2 + 6 H2O
4 x 17 g NH3 ------------ 5 x 28 g N2
?? g NH3 --------------- 300 g N2
300 x 4 x 17 / 5 x 28 =
20400 / 140 => 145.71 g of NH3