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Nimfa-mama [501]
3 years ago
7

Find the 15th term of the arithmetic sequence if a1 = -3 and d = 2

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

25

Step-by-step explanation:

a1 = - 3               Given

d = 2                   Given

n = 15                  Given

Formula

tn = a1 + (n - 1) * d

Substitute and solve

t15 = -3 + (15 - 1) * 2               Calculate what's in the brackets.

t15 = -3 + 14*2                        Combne

t15 = -3 + 28                          Add the two terms

t15 = 25


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Perform each indicated operation
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Answer: \frac{x+6}{x-4}

Step-by-step explanation:

First you need know some general formuals of factorization such as

x^3+y^3=(x+y)(x^2-xy+y^2) so you have x^3+64=X^3+4^3=(x+4)(x^2-4x+4^2)

And, x^2-y^2=(x-y)(x+y) so you have 2x^2-32=2(x^2-16)=2(x^2-4^2)=2(x+4)(x-4)

If you use them, then you can modify your equations such as

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