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allochka39001 [22]
3 years ago
7

According to the balanced equation shown below, 1.00 mole of oxalic acid, h2c2o4, reacts with _________ moles of permanganate io

n, mno4-
Chemistry
1 answer:
zheka24 [161]3 years ago
6 0
The balanced equation that shows the reaction between oxalic acid and permanganate ion in an acidic medium is: 2MnO4- + 5H2C2O4 + 6H+ -> 2Mn(2+) + 10CO2 + 8H2O. Thus, 1 mole of oxalic acid reacts with 0.4 mole of permanganate ion. This was obtained using stoichiometry:

1 mol H2C2O4 x (2 mol MnO4-/ 5 mol H2C2O4) = 0.4 mol MnO4- 

In this redox reaction, the permanganate is reduced to manganese(II) ion.
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A given mass of oxygen occupies 500 ml when the
matrenka [14]
Ok we can use boyle’s law (stating that P is proportional to V) to make the equation (P1V1) =(P2V2).
once we’ve done this, we can plug in the numbers:
(800•500) = (200•V2)
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3 years ago
The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release
KATRIN_1 [288]

The mass of melted gold to release the energy would be  3, 688. 8 Kg

<h3>How to determine the mass</h3>

The formula for quantity of energy is given thus;

Q = n × HF

Where n represents number of moles

HF  represents  heat of fusion

To find the number of moles, we have

235.0 = n × 12.550

number of moles = \frac{235}{12. 550} = 18. 725 moles

Note that molar mass of Gold is 197g/ mol

Let's note that;

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

Mass = 18. 725 × 197

Mass = 3, 688. 8 Kg

Thus, the mass of melted gold to release the energy would be  3, 688. 8 Kg

Learn more about molar heat of fusion here:

brainly.com/question/15634085

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8 0
1 year ago
Paul's doctor says his cardiorespiratory fitness level is excellent, but she worries about Paul's muscular fitness. Paul enjoys
kiruha [24]

Answer:

Explanation:

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3 0
3 years ago
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Which of the following is an example that includes evidence of a chemical reaction?
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3 years ago
Write the ions present in solution of k2co3. express your answers as chemical formulas separated by a comma. identify all of the
GarryVolchara [31]

Answer : The ions present in the solution of K_2CO_3 are K^+ and CO^{2-}_3 in aqueous state.

Explanation :

When K_2CO_3 is in aqueous solution then they dissociates into their ions.

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The charge on potassium ion is +1 and on carbonate ion is -2. To neutralize the charge on carbonate ion, two potassium ion must be used.

Therefore, the ions present in solution of K_2CO_3 are K^+ and [tex]CO^{2-}_3[tex] in aqueous state.

8 0
3 years ago
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