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Jobisdone [24]
3 years ago
11

(Evaluate each logarithm. Use the change of base formula when necessary) helpppp y’all

Mathematics
1 answer:
Dmitry [639]3 years ago
5 0

The value of \log _{6}(36) is 2.

Solution:

Given expression is \log _{6}(36).

<u>To evaluate the expression:</u>

\log _{6}(36)

36 can be written as 6².

       =\log _{6}\left(6^{2}\right)

Using log rule: \log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)

       =2 \log _{6}(6)

Using log rule: \log _{a}(a)=1 so that \log _{6}(6)=1

       = 2(1)

       = 2

\log _{6}(36)=2

Hence the value of \log _{6}(36) is 2.

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c.

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