Question

The power in an electrical circuit is given by the equation P = I2R, where I is the current flowing through the circuit and R is the resistance of the circuit. What is the current in a circuit that has a resistance of 30 ohms and a power of 2 watts

Answer 1

Since we are given the equation P = I2R and the measures of variables in the equation, our first step is to identify each variable.

Since there is a resistance of 30 ohms, R = 30Ω.
Since there is power of 2 watts, P = 2 W.

The variable we are trying to solve for is I, current.

Now we can plug the given information into the equation and solve for I:
$P=I2R \\ 2=I(2)(30) \\ 2=I(60) \\ I= \frac{2}{60} \\ I= \frac{1}{30} =0.033$

Current (I) = 1/30 A, or 0.033 A.

Hope this helps!

Answer 2

Answer:

0.2581 Ampere is the current in a circuit that has a resistance of 30 ohms and a power of 2 watts.

Explanation:

The power (P)in an electrical circuit is given by the equation:

$P=I^2R$

I = Current in the circuit

R = Resistance offered by the circuit

p = 2 watts, R = 30 Ω

I = ?

$2 Watts=I^2\times 30\Omega$

$I=\sqrt{\frac{2 Watts}{30 \Omega}}$

I = 0.2581 Ampere