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2 years ago

An electric Kettle is rated at 25 W. Calculate the quantity of heat generated in 2s

Physics

1 answer:

MatroZZZ [7]2 years ago

4 0

Answer:

Energy consumed by the electric kettle in 9.5 min =Pt=(2.5×10

)×(9.5×60)=14.25×10

Energy usefully consumed =msΔT=3×(4.2×10

)×(100−15)=10.71×10

where s=4.2J/g

C= specific heat of water and boiling point temp=100

Heat lost =14.25×10

−10.71×10

=3.54×10

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What is Biomass?<br> What is Biofuel?<br> Please help me science students

kramer

Answer:

Biomass-Total of mass of organisms in a given area/volume

Biofuel-A fuel directly from living matter.

7 0

2 years ago

A 13561 N car traveling at 51.1 km/h rounds

Minchanka [31]

Answer:

a) The centripetal acceleration of the car is 0.68 m/s²

b) The force that maintains circular motion is 940.03 N.

c) The minimum coefficient of static friction between the tires and the road is 0.069.

Explanation:

a) The centripetal acceleration of the car can be found using the following equation:

$a_{c} = \frac{v^{2}}{r}$

Where:

v: is the velocity of the car = 51.1 km/h

r: is the radius = 2.95x10² m

$a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2}$

Hence, the centripetal acceleration of the car is 0.68 m/s².

b) The force that maintains circular motion is the centripetal force:

$F_{c} = ma_{c}$

Where:

m: is the mass of the car

The mass is given by:

$P = m*g$

Where P is the weight of the car = 13561 N

$m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg$

Now, the centripetal force is:

$F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N$

Then, the force that maintains circular motion is 940.03 N.

c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:

$F_{c} = F_{\mu}$

$F_{c} = \mu N = \mu P$

$\mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069$

Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.

I hope it helps you!

3 0

2 years ago

IP Force to Hold a Baseball A person holds a 1.42-N baseball in his hand, a distance of 34.0 cm from the elbow joint, as shown i

mixer [17]

We will assume that the CM of the arm is at "L" from the elbow, and the ball is at 34cm. Then the net torque is computed by:

Net τ = 1.42 N * 34 cm + 1.50 kg * 9.8m/s² * 34 cm/2 – 12.6 N*2.75cm

= 48.28 N*cm + 1.50kg * 9.8m/s² * 34 cm/2 – 12.6 N*2.75cm

= 48.28 N*cm + 499.8 – 34.65 N*cm

τ = 513.43 N*cm or 5.1343 N*m

6 0

3 years ago

Read 2 more answers

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Nat2105 [25]

The first choice Always given to you by other people

I hope this helped :3

7 0

3 years ago

Read 2 more answers

Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by

QveST [7]

Answer:

0.999958c

Explanation:

Remember that the trip involves traveling for six months at a constant velocity thus returning home at same speed . The time interval of this trip will therefore be one year.

Accurate time interval to be measured by the clock on the spaceship Δt0 = 1.0 years

Time interval as advanced on earth observed from the spacecraft Δt = 110 years

the formula for time dilation is

Δt = Δt0 /√(1-v2/c2)

or v = c*√1-(Δt0/Δt)2

=c*√[1-(1year/110years)2]

= 0.999958c

3 0

2 years ago