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Bess [88]
3 years ago
11

Students asked to measure the temperature of a reaction beaker recorded the following temperatures. 103.7°C, 108.4°C, 105.8°C, 1

04.6°C The actual temperature is 105.1°C. Which measurement is the most precise? 103.7°C 108.4°C 105.8°C 104.6°C
Chemistry
2 answers:
Nata [24]3 years ago
6 0

There are two terms

a) accuracy : it relates to the exactness of an answer that how an answer is close to the actual answer or actual reading

So 104.6 is accurate

b) Precision : This is related to the closeness of different readings with each other

The first reading is 103.7 and the second one is 108.4  so the second reading is quite different from the first reading so it cannot be called as precised

Again 105.8 has good difference from the second reading hence again this is not precised

However the last reading 104.6 is quite near to 105.8 so 104.6 can be called as precise


gtnhenbr [62]3 years ago
6 0
<h2>Answer:</h2>

105.8°C is the most precise measurement.

<h3>Explanation:</h3>

Actual temperature is 105.1°C and recorded values are:

  • 103.7°C
  • 108.4°C
  • 105.8°C
  • 104.6°C

<u>By looking at values 105.8C is nearest to actual value. So it is precise one.</u>

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Of the elements: b, c, f, li, and na. the element with the smallest ionization energy is
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B-  8.2980
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I would say your answer is Na.
8 0
3 years ago
An archer pulls her bowstring back 0.370 m by exerting a force that increases uniformly from zero to 264 N. (a) What is the equi
Arte-miy333 [17]

Answer:

713.51 N/m

Explanation:

Hook's Law: This law states that provided the elastic limit is not exceeded, the extension in an elastic material is directly proportional to the applied force.

From hook's law,

F = ke ...........................Equation 1

Where F = Force exerted on the bowstring, e = Extension/compression of the bowstring, k = Spring constant of the bow.

Make k the subject of the equation,

k = F/e ............................ Equation 2

Given: F = 264 N, e = 0.37 m.

Substitute into equation 2

k = 264/0.37

k = 713.51 N/m

Hence the spring constant of the bow  = 713.51 N/m

3 0
3 years ago
Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.76
aliina [53]

The given question is incomplete, the complete question is:

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?

Answer:

The lowest whole-number mass ratio in the two compounds is 1:2.

Explanation:

There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.  

The no. of moles can be determined by using the formula,  

moles = mass/molecular mass

moles = 2.98 g/207.2 g/mol

= 0.0144 moles

The mass of oxygen in the compound I is 0.461 grams, the molecular mass of oxygen is 16 gram per mol.  

moles = 0.461 g /16 g/mol

= 0.0288 moles

The ratio between the lead and oxygen in the compound I is 0.0144/0.0288 = 1:2

On the other hand, in the compound II, the mass of lead given is 9.89 grams, therefore, the moles of lead in compound II is,  

moles = 9.89 g / 207.2 g/mol

= 0.0477 moles

The mass of oxygen given in compound II is 0.763 grams, the moles of oxygen present in the compound II is,  

moles = 0.763 g / 16 g

= 0.0477 moles

The ratio between the lead and oxygen in the compound II is, 0.0477 moles lead /0.0477 moles oxygen = 1:1

Hence, of the two compounds, the lowest ratio is found in the compound I, that is, 1:2.  

4 0
3 years ago
Is o-toluic acid soluble in ether, NaOH?, Is Napthalene soluble in NaOH?
natima [27]
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8 0
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Extra Stoichiometry Practice
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Answer: 50. 4g

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Now find the mass of aluminium produced.

Mass = moles × molar mass

= 0.72mol × 69.93 mol/g

= 50.4g

8 0
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