Answer:
1. 31.68 moles of water, H₂O
2. 14.81 moles of Cr
Explanation:
1. Determination of the number of mole of water, H₂O.
The balanced equation for the reaction is given below:
C₁₂H₂₂O₁₁ —> 12C + 11H₂O
From the balanced equation above,
1 mole of C₁₂H₂₂O₁₁ produced 12 moles of C and 11 moles of H₂O.
Next, we shall determine the number of mole C₁₂H₂₂O₁₁ needed to produce 34.55 moles of C. This can be obtained as follow:
From the balanced equation above,
1 mole of C₁₂H₂₂O₁₁ produced 12 moles of C.
Therefore, Xmol of C₁₂H₂₂O₁₁ will produce 34.55 moles of C i.e
Xmol of C₁₂H₂₂O₁₁ = 34.55 / 12
Xmol of C₁₂H₂₂O₁₁ = 2.88 moles
Thus, 2.88 moles of C₁₂H₂₂O₁₁ is needed.
Finally, we shall determine the number of mole of water, H₂O produced from the reaction. This can be obtained as follow:
From the balanced equation above,
1 mole of C₁₂H₂₂O₁₁ produced 11 moles of H₂O.
Therefore, 2.88 moles of C₁₂H₂₂O₁₁ will produce = 2.88 × 11 = 31.68 moles of H₂O.
Thus, 31.68 moles of water, H₂O were obtained from the reaction.
2. Determination of the number of mole of Cr needed.
The balanced equation for the reaction is given below:
Cr + H₂SO₄ —> CrSO₄ + H₂
From the balanced equation above,
1 mole of Cr reacted to produce 1 mole of CrSO₄.
Finally, we shall determine the number of mole of Cr needed to produce 14.81 moles of CrSO₄. This can be obtained as follow:
From the balanced equation above,
1 mole of Cr reacted to produce 1 mole of CrSO₄.
Therefore, 14.81 moles of Cr will also react to produce 14.81 moles of CrSO₄.
Thus, 14.81 moles of Cr is needed for the reaction.
