The approximate middle value
Answer:
The merchant buys 30 shirts originally.
Step-by-step explanation:
Let us assume that the merchant bought x numbers of shirts in $120.
So, the cost for each shirt is $
.
Now, if the cost for each shirt is reduced by 1$, then he would have bought 10 shirts more i.e. (x + 10) shirts in $120.
So, we can write the following equation as
⇒(120 - x)(x + 10) = 120x
⇒ 120x - 10x + 1200 - x² = 120x
⇒ x² +10x - 1200 = 0
⇒ x² + 40x - 30x - 1200 = 0
⇒(x + 40)(x - 30) = 0
⇒ x = - 40 or x = 30
But x can not be negative.
Hence, the merchant buys 30 shirts originally. (Answer)
Answer:
.. q T 0 = (q/p)a (q/p)a − (q/p)T−10 if p ≠ q and qT0 = 1 − T0/a if p = q = 1/2.
Step-by-step explanation:
Suppose that there are two different solutions, p and q, in [a, b]. Thus p =g(p) q =g(q) p ≠ q The function g(x) satisfies the hypotheses of the mean-value ... that g(p) –g(q) = (p – q) g׳(t) Because g(p) =p and g(q) = q, the left side of Eq. (1-3) may...
It has turned about 150 degrees going from 2-9 counter clockwise on a clock.