Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
9514 1404 393
Answer:
$6.80/fortnight
Step-by-step explanation:
You need to know there are 13 weeks in a quarter, and 2 weeks in a fortnight. The conversion is straightforward.

Answer:

Step-by-step explanation:
The sum of the interior angles of a polygon with
sides is
. Since the shape in the figure has 5 sides, the sum of its interior angles is
.
Therefore, we can set up the following equation:

Since
and
make up one side of a line, they are supplementary, as each side of a line is
.
Thus, we have:

2:3
it was originally 8:12, but it has to be simplified. 2/3 can also work as an answer.
Answer:
a) P(a)= 0.0001
b) P(b)= 0.0024
Step-by-step explanation:
Given:
Chosen number = 3079
Possible numbers that have chance of winning from 0000 to 9999= 10,000
Winning condition= if made choice matches the winning digits
Now
a)What is the probability that the winning number matches your number exactly?
From 0000 to 9999, only one time can the number 3079 can be the winning number, so
P(a)= 1/10000
= 0.0001
b)What is the probability that the winning number has the same digits as your number in any order?
Winning numbers from 0000 to 10000 that have same digits as 3079 are
4 x 3 x 2 x 1 = 24 ways
Following are the 24 numbers from 0000 to 9999 that have matching digits to 3079:
0379
0397
0973
0937
0793
0739
3079
3097
3970
3907
3790
3709
7039
7093
7930
7903
7390
7309
9073
9037
9370
9307
9730
9703
P(b)= 24/10000
=0.0024 !