Answer:
9.248 < < 9.253 mm
Explanation:
Given data:
standard deviation = 0.021 mm
sample mean = 9.251 mm
total sample = 409 m
confidence interval level = 95%
mean diameter of entire batch
where
- sample mean = 9.251 mm
z = critical value
plugginf all value in the above relation to get the mean diameter
9.248 < < 9.253 mm
The magnitude of shear stress (kPa) on an element a lying at a distance of 20 mm from neutral axis. (6 pts) are given, p = 2kn e = 210gpa distance from constant cease = 20mm = 0.2m.
<h3>What is the cantilever formula?</h3>
The cantilever beam equations (deflection) w = load. l = member length. e = young's modulus. i = the beam's moment of inertia.
- theta= 2000 2*210*10^ 9 * (0.006)^ four 12 [(0.1)^ 2 -(0.08)^ 2 ] =0.1587 rad
- ø at q i.e. x = 100 - 20 = 80mm = 0.08m from loose cease.
- theta = p/(2ei) * (l ^ 2 - x ^ 2) phase of facet a. i = (a ^ four)/12 for square.
Read more about the cantilever beam :
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Answer:
1. 142.1 GPa
2. 98.52%
Explanation:
1. The modulus of elasticity of carbon-epoxy composite is calculated using the following formula:
Ec = VmEm + VfEf
where Vm: volume of Epoxy
Em: modulus of the elasticity of the epoxy
Vf: volume of carbon fiber
Ef: modulus of the elasticity of the carbon fiber
Given that :
Vm = 0.6
Em = 3.5 GPa
Vf = 0.4
Ef: 350 Gpa
Therefore Ec = (0.6 × 3.5 GPa + (0.4 × 350 GPa)
Ec = 142.1 GPa
The modulus of elasticity of carbon-epoxy composite is 142.1 GPa
2. Percentage of load carried by the carbon fibers is given by the following equation: Ff/Fc = (Ef/Ec)×Vf
where Ff is the force carried by carbon fibers, Fc is the force applied to the composite, Ec is the modulus of elasticity of the composite, Ef is the modulus of the elasticity of the carbon fiber and Vf the volume of carbon fiber.
Given that:
EF = 350 Gpa
Ec = 142.1 GPa
Vf = 0.4
Substituting the above values into the equation:
Ff/Fc = (350 GPa/142.1 GPa)×0.4 = 0.9852 = 98.52%
The percentage of load carried by the carbon fibers is there 98.52%
Answer
The skateboarder applies pressure to the trucks and gives/releases pressure on the levers. Second, the wheels and the axles are also examples of simple machines. They help the skater ride, spin, grind, and do a bunch of other radical movements on a skateboard.:
Explanation:
Answer:
a) 156 meters
b) 58 m/s
c) 9.8 m/s^2
Explanation:
a) The horizontal displacement X = V *t
X = 50 * 3 = 150 meters
Vertical displacement = y = – g * t² / 2
Y = -9.8 *3*3/2 = -4.9*9 = 44.1
Net Displacement = Sqrt (X^2 +Y^2) = 156.34 = 156 meters
b) Speed of the projectile
vx = 50 m/s
vy = t*g = 9.8*3 = 29.4
V = Sqrt (vx^2 + vy^2) = 58 m/s
c) Acceleration is the acceleration due to gravity = 9.8 m/s^2