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Jlenok [28]
4 years ago
13

Most motor vehicle crashes in Florida in 2016 occurred on

Engineering
2 answers:
vlada-n [284]4 years ago
4 0
Most Motor Vehicle catches in Florida in 2016 occurred on Motorcycles. Another option could be roads.
Bad White [126]4 years ago
3 0

Answer:

Holidays

Explanation:

The reason of holidays is holidays are generally a time of increased travel.

In 2016, Thanksgiving Day was the holiday period with the most motor vehicle deaths (439), followed by Independence Day (397), Memorial Day (389), Labor Day (379), Christmas Day (318) and New Year’s Day Day (279).

I hope it helps

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A signal expected to be of the form F(t)=10sin15.7t is to be measured with a first-order instrument having a time constant of 50
svet-max [94.6K]

Answer:

The answer is attached below

Explanation:

5 0
4 years ago
Jelena is 26 and has worked in the service industry for most of her work history. She is willing to advance her education and tr
katrin2010 [14]
Customer service

Since she has reckless driving and her record, anything involving driving of some sorts mechanics as well won’t work well with her!! Hope this helps
8 0
3 years ago
hi i am a teacher and i want to say to stop using brainly we strictly banned brainly but our students keep using it
Masja [62]

Answer:

Then miss try to get your school to banned it for your district like forbid then from the web site then it will not allow them to use it. then sometimes use it to help other people who needs help like teachers do or we need help with something we dont know so we ask for help for a better understanding of it.

Explanation:

^-^ hope you have a good day miss or sir

4 0
3 years ago
La viscosidad de un liquido es igual a 0.04 N s/m^2 . Este valor en Dinas s/cm^2 se encuentra en el literal
nadezda [96]

Answer:

0.4 Dinas*s/cm^2

Explanation:

Tenemos una viscosidad:

V = 0.04 N*s/m^2

Y queremos reescribir esto en Dinas*s/cm^2

Primero transformemos la unidad del denominador, es decir, tenemos que pasar de 1/m^2 a 1/cm^2

Para ello, usamos que:

1m = 100cm

entonces:

(1m/100cm) = 1

Si elevamos ambos lados al cuadrado, obtenemos:

(1m/100cm)^2 = 1

Ahora podemos multiplicar el valor de la viscosidad por esto (que es igual a 1)

V = 0.04 N*s/m^2*((1m/100cm)^2 = 0.00004 N*s/cm^2

Ahora debemos convertir de Newtons a Dinas

Sabemos que:

1 N = 100,000 dinas

1 = (100,000 dinas/1N)

Entonces, de vuelta podemos multiplicar nuestra viscosidad por  (100,000 dinas/1N), que es igual a 1 (asi que no cambia el valor, solo sirve para cambiar las unidades)

0.00004 N*s/cm^2 = (100,000 dinas/1N)*(0.00004 N*s/cm^2)

                                 = (100,000 dinas)*(0.00004 s/cm^2)

                                 = 0.4 Dinas*s/cm^2

5 0
3 years ago
Determine the carburizing time necessary to achieve a carbon concentration of 0.30 wt.% at a position of 4 mm into an iron-carbo
Amiraneli [1.4K]

Answer:

the carburizing time necessary to achieve a carbon concentration is 31.657 hours

Explanation:

Given the data in the question;

To determine the carburizing time necessary to achieve the given carbon concentration, we will be using the following equation:

(Cs - Cx) / (Cs - C0) = ERF( x / 2√Dt)

where Cs is Concentration of carbon at surface = 0.90

Cx is Concentration of carbon at distance x = 0.30 ; x in this case is 4 mm = ( 0.004 m )

C0 is Initial concentration of carbon = 0.10

ERF() = Error function at the given value

D = Diffusion of Carbon into steel

t = Time necessary to achieve given carbon concentration ,

so

(Cs - Cx) / (Cs - C0) = (0.9 - 0.3) / (0.9 - 0.1)

= 0.6 / 0.8

= 0.75

now, ERF(z) = 0.75; using ERF table, we can say;

Z ~ 0.81; which means ( x / 2√Dt) = 0.81

Now, Using the table of diffusion data

D = 5.35 × 10⁻¹¹ m²/sec at (1100°C) or 1373 K

now we calculate the carbonizing time by using the following equation;

z = (x/2√Dt)

t is carbonizing time

so we we substitute in our values

0.81 = ( 0.004 / 2 × √5.35 × 10⁻¹¹ × √t)

0.81 = 0.004 / 1.4628 × 10⁻⁵ × √t

0.81 × 1.4628 × 10⁻⁵ × √t = 0.004

1.184868 × 10⁻⁵ × √t = 0.004  

√t = 0.004 / 1.184868 × 10⁻⁵

√t = 337.5903

t = ( 337.5903)²  

t = 113967.21 seconds

we convert to hours

t = 113967.21 / 3600

t = 31.657 hours

Therefore, the carburizing time necessary to achieve a carbon concentration is 31.657 hours

4 0
2 years ago
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