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marshall27 [118]
3 years ago
14

D 4.37. Assuming the availability of diodes for which vD = 0.75 V at iD = 1mA, design a circuit that utilizes four diodes connec

ted in series, in series with a resistor R connected to a 15-V power supply. The voltage across the string of diodes is to be 3.3 V.
Engineering
1 answer:
gregori [183]3 years ago
6 0

Answer:

R = 0.5825 k ohm

Explanation:

given data

vD = 0.75 V

iD = 1mA

resistor R = 15-V

solution

we get here first vD that is

vD = \frac{3.3}{4}  

vD = 0.825

so

iD = Ise × e^{\frac{vD}{nvT}}      

n = 1

so we can say

\frac{iD2}{iD1} = e^{\frac{vD2-vD1}{nvT}}  

so it will

iD2 = iD1 × e^{\frac{vD2-vD1}{nvT}}

put here value and we get

iD2 = 1 × e^{\frac{0.825-0.75}{25}}  

iD2 = 1 × e^{3}  

iD2 = 20.086 mA

so

R will be

R = \frac{15-3.3}{ID}  

R = 0.5825 k ohm

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Serggg [28]

Answer:

Explanation:

Code used will be like

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

namespace PaintingWall

{

class Room

{

public int length, width, height,Area,Gallons;

public Room(int l,int w,int h)

{

length = l;

width = w;

height = h;  

}

private int getLength()

{

return length;

}

private int getWidth()

{

return width;

}

private int getHeight()

{

return height;

}

public void WallAreaAndNumberGallons()

{

Area = getLength() * getHeight() * getWidth();

if (Area < 350)

{

Gallons = 1;

}

else if (Area > 350)

{

Gallons = 2;

}    

Console.WriteLine ("The area of the Room is " + Area);

Console.WriteLine("The number of gallons paint needed to paint the Room is " + Gallons);

}

 

}

class PaintingDemo

{

static void Main(string[] args)

{

int l, w, h;

Room[] r = new Room[8];

for (int i = 0; i <= 7; i++)

{

Console.WriteLine("Room "+(i+1));

Console.Write("Enter Length : ");

l = Convert.ToInt32(Console.ReadLine() );

Console.Write("Enter Width : ");

w = Convert.ToInt32(Console.ReadLine());

Console.Write("Enter Height : ");

h= Convert.ToInt32(Console.ReadLine());

r[i] = new Room(l,w,h);

Console.WriteLine();

}

for (int i = 0; i <= 7; i++)

{

Console.WriteLine("Room " + (i + 1));

r[i].WallAreaAndNumberGallons();

}

Console.ReadKey();  

}

}

}

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Answer:

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Explanation:

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