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Answer:
Maximum force, F = 1809.55 N
Explanation:
Given that,
Diameter of the anterior cruciate ligament, d = 4.8 mm
Radius, r = 2.4 mm
The tensile strength of the anterior cruciate ligament, 
We need to find the maximum force that could be applied to anterior cruciate ligament. We know that the unit of tensile strength is Pa. It must be a type of pressure. So,

So, the maximum force that could be applied to anterior cruciate ligament is 1809.55 N
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Answer:

Given:
Temperature, T = 3.13 K
molar mass of molecular hydrogen, m = 2.02 g/mol = 
Solution:
To calculate the root mean squarer or rms speed of hydrogen molecule, we use the given formula:

where
R = rydberg's constant = 8.314 J/mol-K
Putting the values in the above formula:


Answer:
Explanation:
The difference between a bound orbit and an unbound orbit around the sun is that:
An object on a bound orbit pursues the same way around the Sun again and again, while an object on an unbound orbit moves toward the Sun only a single time and afterward stays away forever & never returns.