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Verdich [7]
3 years ago
11

A steady 45 N horizontal force is applied to a 15 kg object a table. The object slides against a friction force of 30 N. Calcula

te the acceleration of the object in m/s.
Physics
1 answer:
lisov135 [29]3 years ago
6 0

The net force on an object subject to friction is equal to the sum of the applied force and the frictional force.

Mathematically,

F_{N} = ma = F_{applied} - f_{fr}

Here, m is mass of object and a is its acceleration. We take frictional force negative because it opposes the motion of object.

Given, m=15\ kg , F_{applied} =45\ N and f_{fr} = 30\ N

Substituting these values in above formula, we get

15\ kg\times a = 45\ N -30\ N=15\ N \\\\a=\frac{15\ N}{15\ kg} =1\ m/s^2.

Thus, the acceleration of an object is 1\ m/s^2.


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A long, thin superconducting wire carrying a 17 A current passes through the center of a thin, 3.0-cm-diameter ring. A uniform e
nalin [4]

Answer:

a

 \frac{dE}{dt} =-  2.72 *10^{15} \  N/C \cdot s

b

The  direction of the electric field is opposite that of the current              

Explanation:

From the question we are told that

   The current is  I  =  17\ A

   The diameter of the ring is  d =  3.0 \ cm  = 0.03 \ m

   

Generally the  radius is mathematically represented as

       r =  \frac{d}{2}

       r =  \frac{0.03}{2}

       r =  0.015 \  m

The  cross-sectional area is mathematically represented as

       A =  \pi r^2

=>     A = 3.142 *  (0.015^2)

=>    A = 7.07 *10^{-4 } \  m^ 2

Generally  according to ampere -Maxwell equation we have that

      \oint \= B \cdot  \= ds =  \mu_o  I + \epsilon_o  \mu _o\frac{ d \phi }{dt }

Now given that \= B  =  0 it implies that

     \oint \= B \cdot  \= ds = 0

So

    \mu_o  I + \epsilon_o  \mu _o\frac{ d \phi }{dt } = 0

Where  \epsilon _o is the permittivity of free space with value \epsilon_o  =  8.85*10^{-12 } \   m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

            \mu_o is the permeability of free space with value  

\mu_o  =   4\pi * 10^{-7} N/A^2

      \phi is magnetic flux which is mathematically represented as

       \phi  =  E * A

Where E is the electric field strength

  So  

       \mu_o  I + \epsilon_o  \mu _o   \frac{ d [EA] }{dt }  = 0

=>   \frac{dE}{dt} =-  \frac{I}{\epsilon_o * A }

=>   \frac{dE}{dt} =-  \frac{17}{8.85*10^{-12} * 7.07*10^{-4} }

=>   \frac{dE}{dt} =-  2.72 *10^{15} \  N/C \cdot s

The  negative  sign shows that the  direction  of  the electric field is opposite that of the current

           

       

8 0
3 years ago
The gravitational force on a baseball is 1.4 N. What is its mass? Round to two decimal places.
valina [46]

Answer:

0.14 kg

Explanation:

W = mg

1.4 N = m (9.8 m/s²)

m = 0.14 kg

8 0
3 years ago
Within the solar system, the strongest magnetic field exists around _____.
trapecia [35]
The answer is the sun.
5 0
4 years ago
Read 2 more answers
The ideal mechanical advantage of a pulley system is equal to the?
marishachu [46]

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Explanation:

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The ideal mechanical advantage of a pulley system is equal to the number of rope segments which is supporting the load. More the rope segments, It is more helpful to do the lifting the work.

It means that less force is needed for this task to complete.

Therefore, the correct option is (C).

7 0
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den301095 [7]

Answer:

The bomb will remain in air for <u>17.5 s</u> before hitting the ground.

Explanation:

Given:

Initial vertical height is, y_0=1500\ m

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The displacement of the bomb vertically is S=y-y_0=0-1500=-1500\ m

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Therefore, the displacement of the bomb is given as:

S=u_yt+\frac{1}{2}gt^2\\-1500=0-\frac{1}{2}(9.8)(t^2)\\1500=4.9t^2\\t^2=\frac{1500}{4.9}\\t=\sqrt{\frac{1500}{4.9}}=17.5\ s

So, the bomb will remain in air for 17.5 s before hitting the ground.

6 0
4 years ago
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