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4 years ago

when there are equal forces from opposite directions acting on an object the forces are said to be which of the following

Mathematics

1 answer:

svetoff [14.1K]4 years ago

8 0

Answer: Balanced Forces

Step-by-step explanation:

Since both of the forces are equal and going opposite directions on an object, the object will not move and the forces are then identified as Balanced Forces. Therefore, the net force is equal to 0.

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A study found that the mean amount of time cars spent in drive-throughs of a certain fast-food restaurant was 157.4 seconds. A

Oduvanchick [21]

Answer:

a) The probability that a randomly selected car will get through the restaurant's drive-through in less than 105 seconds is 5.59%.

b) The probability that a randomly selected car will spend more than 195 seconds in the restaurant's drive-through is 12.71%

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

A study found that the mean amount of time cars spent in drive-throughs of a certain fast-food restaurant was 157.4 seconds. This means that $\mu = 157.4$

Assuming drive-through times are normally distributed with a standard deviation of 33 seconds. This means that $\sigma = 33$ .

(a) What is the probability that a randomly selected car will get through the restaurant's drive-through in less than 105 seconds?

This probability is the pvalue of the zscore of $X = 105$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{105 - 157.4}{33}$

$Z = -1.59$

$Z = -1.59$ has a pvalue of .0559. This means that there is a 5.59% probability that a randomly selected car will get through the restaurant's drive-through in less than 105 seconds,

(b) What is the probability that a randomly selected car will spend more than 195 seconds in the restaurant's drive-through?

This is 1 subtracted by the pvalue of the zscore of $X = 195$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{195 - 157.4}{33}$

$Z = 1.14$

$Z = 1.14$ has a pvalue of .87286. This means that there is a 87.286% probability that a randomly selected car will get through the restaurant's drive-through in less than 195 seconds.

So the probability that a randomly selected car will spend more than 195 seconds in the restaurant's drive through is

$P = 1 - .87286 = .1271$

7 0

3 years ago

If you roll a six sided die three times, how many possible outcomes are there?

Andrej [43]

The Fundamental Counting Principle

Rolling two six-sided dice: Each die has 6 equally likely outcomes, so the sample space is 6 • 6 or 36 equally likely outcomes.

6 0

3 years ago

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The product of two numbers is 41. One of the numbers

shepuryov [24]

<h3>Answer: 5 - 4i (choice A)</h3>

===================================================

Work Shown:

x = the other number

(5+4i)*x = 41

x = 41/(5+4i)

x = 41*(5-4i)/( (5+4i)*(5-4i) ) ..... see note below

x = 41*(5-4i)/( 41 )

x = (41/41)*(5-4i)

x = 5 - 4i

As a way to check, (5+4i)*(5-4i) = 5^2+4^2 = 25+16 = 41

The rule used is (a-bi)(a+bi) = a^2 + b^2

-----------

Note: I multiplied top and bottom by (5-4i) to get rid of the imaginary term in the denominator.

3 0

3 years ago

-2/5 - (-2/5) plz help il reward you

polet [3.4K]

zero

double - is actually plus

4 0

3 years ago

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The perimeter of a regular hexagon is 84 cm. What is the length of one side?

bonufazy [111]

Answer:

14cm

Step-by-step explanation:

As we know , hexagon has six sides .

so ,

We will divide the number of sides by the total perimeter to obtain the length of one side :

_____________________

Hexagon = 6 sides .

Length of one side of hexagon would be = 84/6

=> 14 cm

3 0

3 years ago

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