Answer:
electric filed is 907 N/C
Explanation:
Given data
surface of area = 0.321 m²
electric flux of 123 N.m²/C
angle = 25°
to find out
magnitude of the electric field
solution
we know flux formula that is
flux = electric filed × area
put all value
123 = electric filed × 0.321 sin(25)
electric filed = 123 / 0.321 sin(25)
electric filed = 906.67
so electric filed is 907 N/C
Average speed = (total distance) / (total time)
Total distance = 59 km + 74 km = 133 km
Total time = 3 hrs + 5 hrs = 8 hrs
Average speed = (133 km) / (8 hrs) = 16.625 km/hr
Answer:
17.2 seconds
Explanation:
Given:
v₀ = 0 m/s
a₁ = 10.0 m/s²
t₁ = 3.0 s
a₂ = 16 m/s²
t₂ = 5.0 s
a₃ = -12 m/s²
v₃ = 0 m/s
Find: t
First, find v₁:
v₁ = a₁t₁ + v₀
v₁ = (10.0 m/s²) (3.0 s) + (0 m/s)
v₁ = 30 m/s
Next, find v₂:
v₂ = a₂t₂ + v₁
v₂ = (16 m/s²) (5.0 s) + (30 m/s)
v₂ = 110 m/s
Finally, find t₃:
v₃ = a₃t₃ + v₂
(0 m/s) = (-12 m/s²) t₃ + (110 m/s)
t₃ = 9.2 s
The total time is:
t = t₁ + t₂ + t₃
t = 3.0 s + 5.0 s + 9.2 s
t = 17.2 s
Round as needed.
Answer:
P.E = 25.48 Joule
Explanation:
Here,
mass (m) = 2kg
height (h) = 1.3m
g = 9.8m/s^2
P.E = mgh
= (2) (9.8) (1.3)
P.E = 25.48 Joule
Thus, the potential energy of a 2kg plant that is on a windowsill 1.3m high is 25.48 Joule
-TheUnknownScientist
Answer:
x(t) = 0.077cos(6.455t)
Explanation:
If the spring can be stretched 0.2 m by a force of 50 N, then the spring constant is:
k = 50 / 0.2 = 250 N/m
The equation of simple harmonic motion is as the following:
where 
We also know that the initial velocity is 0.5 m/s, which is also the maximum speed at the equilibrium:
is the initial phase
Therefore, the position of the mass after t seconds is
x(t) = 0.077cos(6.455t)
