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salantis [7]
3 years ago
9

Which statement best describes the function of capillaries, arteries, and veins in the circulatory system? A. Capillaries delive

r blood to individual cells; arteries bring oxygen-depleted blood back to the heart; veins deliver oxygen-rich blood to the heart. B. Capillaries deliver oxygen-rich blood to the heart; arteries bring oxygen rich-blood away from the heart; veins deliver blood to individual cells. C. Capillaries deliver blood to individual cells; veins generally deliver oxygen-depleted blood to the heart; arteries generally bring oxygen-rich blood away from the heart. D. Capillaries bring oxygen-rich blood away from the heart; arteries deliver blood to individual cells; veins deliver oxygen-rich blood to the heart.
Chemistry
2 answers:
Oliga [24]3 years ago
4 0
The CORRECT answer is C. Capillaries deliver blood to individual cells; veins generally deliver oxygen-depleted blood to the heart; arteries generally bring oxygen-rich blood away from the heart.
kondor19780726 [428]3 years ago
3 0
The answer is a. The arteries are red and transfer blood to the heart. Veins are blue and transfer blood away from the heart and to all of the different parts of the body. The capillaries are in-between the veins and arteries and provide blood to cells.

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Use bond energies to calculate δhrxn for the reaction. n2(g)+3cl2(g)→2ncl3(g)
Jobisdone [24]
ΔHrxn = ΣδΗ(bond breaking) - ΣδΗ(bond making)

Bond enthalpies,
N ≡ N ⇒ 945 kJ mol⁻¹
N - Cl ⇒ 192 kJ mol⁻¹
Cl - Cl⇒ 242 kJ mol⁻¹

According to the balanced equation,
ΣδΗ(bond breaking)  = N ≡ N x 1 + Cl - Cl x 3
                                  = 945 + 3(242)
                                  = 1671 kJ mol⁻¹
ΣδΗ(bond making)    = N - Cl x 3 x 2
                                 = 192 x 6
                                 = 1152 kJ mol⁻¹

δHrxn = ΣδΗ(bond breaking) - ΣδΗ(bond making)
          = 1671 kJ mol⁻¹ - 1152 kJ mol⁻¹
          = 519 kJ mol⁻¹
3 0
4 years ago
Read 2 more answers
ASAP I WILL GIVE BRAINLIEST!Which arrow represents the change of state described above? The diagram shows changes of state betwe
lilavasa [31]

Answer:

O

Explanation:

The atoms lose energy during a change of state, but can still slide past each other; gas to a liquid.

7 0
3 years ago
19. When an atom of iron loses all of its 4s electrons and one of its 3d electrons, what is its charge?
Snowcat [4.5K]
Its charge would be the amount of electrons that are lost in total, which the information is not stated

7 0
3 years ago
What is the density of a block marble that occupies 255 cm^3 and has a mass of 1000g
RUDIKE [14]

Answer:

<h2>3.92 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{1000}{255}  \\  = 3.921568...

We have the final answer as

<h3>3.92 g/cm³</h3>

Hope this helps you

4 0
3 years ago
Determine if each statement is True or False. [ Select ] Central atoms with four electron groups will be sp3 hybridized. [ Selec
meriva

Answer:

Central atoms with four electron groups will be sp3 hybridized. True

Hybrid orbitals are delocalized over the entire molecule. False

The number of hybrid orbitals is equal to the number of atomic orbitals that are blended together. True

Atoms with a single pi bond and an octet are sp2 hybridized. True

Sometimes oxygen atoms will be sp3d hybridized in organic molecules. False

All resonance structures must be considered when assigning hybridization. False

Explanation:

When a central atom has four electron groups attached to it, then it must be sp3 hybridized. This is the case in ammonia, water, hydrogen sulphide, methane etc.

Hybridization is a valence bond concept while delocalization is a molecular orbital theory concept. Hybridized orbitals are localized on central atoms in a molecule while delocalized orbitals spread across the entire molecule.

According to valence bond theory, the number of atomic orbitals that combined to give hybrid orbitals must be equal to the number of hybrid orbitals formed.

When an atom has a single pi bond and on octet of electrons, then it must be sp2 hybridized. Remember that in ethene for instance, carbon has one pi bond and an octet of electrons.

Oxygen has an empty n=3 level hence it can not have d-orbitals involved in hybridization.

The electron domain geometry of the molecule is considered when assigning hybridization and not the resonance structures. All the resonance structures must have the central atom in the same hybridization state.

8 0
3 years ago
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