The range of a function is the set of all the possible function outputs. We know that sin theta varies between -1 and 1 if we draw a graph. According to the graph, the largest number that is an output of g is -1, and the smallest number is 1. Every number between them is also an output of g for some input. Therefore, the range of g is [-1,1].
Answer:
q = 3 + 1/2r
Step-by-step explanation:
10q - 5r = 30
We want to solve for q
Add 5r to each side
10q - 5r+5r = 30+5r
10q = 30+5r
Divide by 10
10q/10 = 30/10 +5r/10
q = 3 + 1/2r
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Answer:
it is not a good estimate.
Step-by-step explanation:3816 can be rounded to 4000 and 467 can be rounded to 500. Adding 4000+500 gives 4500, which isn't near 8000.
i hoped this helped :)
<3
