Write each mixed number as as a decimal. Use bar notation if the decimal is repeating.

A compound with a molar mass of 102.133 g/mol contains an element with a subscript of 5 . the element is 58.80 g per 100.0 g com

VLD [36.1K]

Answer:

12.0108408

Explanation:

Denote the element with a letter like say X. Since it has a subscript of 5, then, X5.

Molecular mass=102.133g/mol.

% of X in compound =58.8/100

=0.588

Mass of X in the compound = 0.588*102.133 ( the % of X in compound * molar mass of compound)

= 60.054204

X5=60.054204

Then element X has a mass of 60.054204/5=12.0108408

6 0

3 years ago

PLEASEEE HELPPPP ASAP!!

Goshia [24]

Atoms are made up of three subatomic particles called protons, neutrons, and electrons.

Protons and neutrons are located in the nucleus.

All protons have a positive charge.

All neutrons have no charge or are neutral.

Electrons orbit around the nucleus and have a negative charge.

8 0

3 years ago

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If the reaction N2 (g) + 3 H2 (g) --> 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo

Luba_88 [7]

<u>Answer:</u> The value of $K_c$ is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

The expression for the $K_{c}$ is given as:

$K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}$

We are given:

$[NH_3]=0.25M$

$[H_2]=0.75M$

$[N_2]=1.1M$

Putting values in above equation, we get:

$K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}$

$K_c=0.135$

There are 3 conditions:

When $K_{c}>1$ ; the reaction is product favored.
When $K_{c}$ ; the reaction is reactant favored.
When $K_{c}=1$ ; the reaction is in equilibrium.

For the given reaction, the value of $K_c$ is less than 1. Thus, the reaction is reactant favored.

Hence, the value of $K_c$ is 0.136 and is reactant favored.

4 0

3 years ago

Select the correct answer from the drop-down menu. a scientist digs up sample of arctic ice that is 458,000 years old. he takes

Jlenok [28]

The original mass of krypton 81 that is present in the ice is 6.70 grams.

<h3>How do we calculate original mass?</h3>

Original mass of any substance will be calculated as below for the decomposition reaction is:

N = N₀(1/2)ⁿ, where

N = remaining mass of krypton-81 = 1.675g

N₀ = original mass of krypton-81 = ?

n will be calculated as:
n = T/t, where

T = total time period = 458,000 years

t = half life time = 229,000 years

n = 458,000/229,000 = 2

Now putting all these values on the above equation, we get

N₀ = 1.675 / (1/2)²

N₀ = 6.70 g

Hence required mass is 6.70 g.

To know more about half life time, visit the below link:
brainly.com/question/2320811

8 0

2 years ago

36. Dimensional Analysis: A useful way to convert units using multiplication & division *Always start with what you are give

ollegr [7]

Answer:

A) 7.9 x 10⁶ inches

B) 1004 g

C) 2.8 x 10³ inches/ min

D) 1.2 x 10⁻⁴ mm

Explanation:

A) Since 39.37 inches = 1 m, you can convert meters to inches by multiplying by the conversion factor (39.37 inches / 1 m).

Notice that if 39.37 inches = 1 m then 39.37 inches / 1 m = 1. That means that when you multiply by a conversion factor, you are only changing units since it is the same as multiplying by 1 :

2.0 x 10⁵ m * (39.37 inches / 1 m) = 7.9 x 10⁶ inches

B) Conversion factors : (2.205 pounds / 1 kg) and (453.59 g / 1 pound), because 2.205 pounds = 1 kg and 1 pound = 453.59 g. Then:

1.004 kg * ( 2.205 pounds / 1 kg) * ( 453.59 g / 1 pound) = 1004 g

C) Conversion factor: (39.37 inches / 1 m) and (60 s / 1 min)

1.2 m/s * (39.37 inches / 1 m) * ( 60 s / 1 min) = 2.8 x 10³ inches/ min

D)Converison factor ( 1 mm / 1 x 10⁶ nm):

120 nm (1 mm / 1 x 10⁶ nm) = 1.2 x 10⁻⁴ mm

3 0

3 years ago

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