Question

2. A linearly-polarized em wave moving in vacuum perpendicular to a perfectly reflecting surface exerts a radiation pressure of 518 Pa on that surface. Find the intensity of that em eave.

Answer 1

Answer:

The intensity of that em eave is $1554\times10^{8}\ W/m^2$

Explanation:

Given that,

Pressure = 518 Pa

We need to calculate the intensity of that em eave

Using formula of pressure

$P=\dfrac{I}{c}$

$I=Pc$

Where,I =  intensity of em eave

c = speed of light

P = pressure

Put the value into the formula

$I=518\times3\times10^{8}$

$I=1554\times10^{8}\ W/m^2$

Hence, The intensity of that em eave is $1554\times10^{8}\ W/m^2$