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max2010maxim [7]
3 years ago
12

if two displacement vectors add to yeild a totsl displacement of zero, what do you know about the two displacements​

Physics
1 answer:
vivado [14]3 years ago
4 0

That the vectors are in opposite directions from each other and are the same distance.

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How many electrons will constitute 2A current in unit time
soldi70 [24.7K]

Answer:

2 charges of electron (2C)

Explanation:

I = Q/t

2 = Q/1

Q = 2×1= 2C

Q = 2 charge of electron

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3 years ago
What type of wave shows wave-particle duality? Mechanical or Electromagnetic?
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Mechanical wave shows dual nature
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Use Hooke's Law, which states that the distance a spring stretches (or compresses) from its natural, or equilibrium, length vari
Phantasy [73]

Answer:

706.68 N

Explanation:

By Hooke's law,

F = ke

k=\dfrac{F}{e}

Using the values in the question,

k=\dfrac{265\text{ N}}{0.15 \text{ m}}=1766.7\text{ N/m}

When e = 0.4 m,

F = 1766.7\text{ N/m}\times0.4\text{ m}=706.68\text{ N}

6 0
3 years ago
Carbon is allowed to diffuse through a steel plate 9.7-mm thick. The concentrations of carbon at the two faces are 0.664 and 0.3
cupoosta [38]

Answer:

844°C

Explanation:

The problem can be easily solve by using Fick's law and the Diffusivity or diffusion coefficient.

We know that Fick's law is given by,

J = - D \frac{\Delta c}{\Delta x}

Where \frac{\Delta c}{\Delta x} is the concentration of gradient

D is the diffusivity coefficient

and J is the flux of atoms.

In the other hand we have, that

D= D_0 e^{\frac{E_d}{RT}}

Where D_0 is the proportionality constant,

R is the gas constant, T the temperature and E_d is the activation energy.

Replacing the value of diffusivity coefficient in Fick's law we have,

J = -D_0 ^{\frac{E_d}{RT}}\frac{\Delta c}{\Delta x}

Rearrange the equation to get the value of temperature,

T=\frac{Ed}{Rln(\frac{J\Delta x}{D_0 \Delta c})}

We have all the values in our equation.

\Delta c = 0.664-0.339 = 0.325 C. cm^{-1}

\Delta x = 9.7*10^{-3}m

E_d = 82000J

D_0 = 6.5*10^{-7}m^2/s

J = 3.2*10^{-9}m^2/s

R= 8.31Jmol^{-1}K

Substituting,

T=\frac{Ed}{Rln(\frac{J\Delta x}{D_0 \Delta c})}

T=-\frac{-82000}{(8.31)ln(\frac{3.2*10^{-9}(9.7*10^{-3})}{6.5*10^{-7} (0.325)})}

T=1118.07K=844\°C

4 0
4 years ago
The average distance from earth to the sun is 150 megameters. what is that distance in meters?
alexira [117]
It is 150,000,000 meters!!
7 0
4 years ago
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