Question

A balloon tied to the ground with a rope floats in the air. The volume of the balloon is 1 L and the pressure in the balloon is 0.8 atm. If the balloon is put into a glass container under water which compresses it so the balloon is 4 atm, what will be the new volume of the balloon?

Answer 1

Answer:

V₂=0.2 L

Explanation:

Given that

At initial condition :

Volume ,V₁ = 1 L

Pressure ,P₁ = 0.8 atm

At final condition :

P₂ = 4 atm

The final volume = V₂

If the temperature of the gas is constant then

V₁P₁= V₂P₂

$V_2=V_1\dfrac{P_1}{P_2}$

$V_2=1\times \dfrac{0.8}{4}\ L$

V₂=0.2 L

That is why the new volume will be 0.2 L.