Answer:
Standard enthalpy of formation of Carbon disulfide CS2 = 87.3 KJ/mol
Explanation:
forming CS2 means that it should in the product side
C(graphite) + O2 → CO2 ΔH = -393.5
2S(rhombic) + 2O2 → 2SO2 ΔH = -296.4 x 2
CO2 + 2SO2 → CS2 + 3O2 ΔH = -1073.6 x -1
the second reaction is multiplied by 2 so that the SO2 and O2 can cancel out.
the third reaction is reversed (multiplied by -1) so that CS2 will be on the product side.
after adding the reaction and cancelling out similarities, the final reaction is: C(graphite) + 2S(rhombic) → CS2
Add ΔH to find the enthalpy of formation of CS2
ΔHf = (-393.5) + (-296.4 x 2) + (-1073.6 x -1) = 87.3 KJ/mol
be aware of signs
Answer:
Iron is being oxidized at the anode and water is acting as the electrolyte.
Explanation:
When iron is exposed to oxygen and water , the rusting of iron takes place.
<u>The reaction taking place at anode : Oxidation of iron.</u>
The reaction taking place at cathode : Reduction of oxygen in the air.
The overall reaction:
The rust that is hydrated iron(III) oxide can form iron(II) ions which can react further with oxygen.
Thus, from the above reactions ,
Iron is being oxidized at the anode and water is acting as the electrolyte.
Solids are things like wood, salt, your face, shoes. they all keep their shapes. they can be compacted if you squish them. they have a defined shape and volume.
