Ask question

Ask question

All categories

3 years ago

7

Which of the following devices is based on the property of thermal expansion?

2 answers:

earnstyle [38]3 years ago

6 0

D. thermometer. The warmer it gets, the more energy the particles gain and the more they move and 'expand', rising up the thermometer.

borishaifa [10]3 years ago

5 0

The correct answer to the question is : D) Thermometre

EXPLANATION:

Thermometre is the device used for measuring the temperature of any substance.

Thermal expansion is the process in which the substance will expand when heat is given to that substance. Thermometre is based on the property of thermal expansion.

Generally, the substance that is used in thermometre is mercury. It expands at a fast rate when a little bit of heat is given to the thermometre.

When the thermometre is connected to any body, the heat will flow from body at high temperature to thermometre. The mercury level rises in the thermometre tube which gives the temperature of that substance under consideration.

Hence, it is the thermometre which is based on thermal expansion.

You might be interested in

How do i figure out this question?

nikklg [1K]

Answer:

0.75 g/cm^3

Explanation:

The formula for density:

$\rho = \frac{m}{V}$

Where m is the mass and V is the volume.

So, we can substitute values for m and V:

$\rho = \frac{277}{370}\approx0.75$

Therefore, the density is 0.75 g/cm^3 (watch the units!)

8 0

3 years ago

Read 2 more answers

A rectangular barge, 5.2 m long and 2.4 m wide, floats in fresh water. Suppose that a 410-kg crate of auto parts is loaded onto

sesenic [268]

<h2>Answer:</h2><h2>The depth of barge float=3 cm</h2><h2>Explanation:</h2>

Length of rectangular barge=5.2 m

Width of rectangular barge=2.4m

Mass of crate=410 kg

Let h be the height of barge float

Volume of barge float= $l\times b\times h=5.2\times 2.4\times h=12.48h$

Density of water= $10^3kg/m^3$

Weight of water displaced by barge=Buoyant force=-Weight of horse

$Volume\;of\;water\times density\;of\;water\times g=410\times g$

$12.48h\times 1000=410$

$h=\frac{410}{12.48\times 1000}=0.03 m$

1 m=100 cm

$0.03 m=0.03\times 100=3$ cm

Hence, the depth of barge float=3 cm

<h2 />

4 0

3 years ago

Read 2 more answers

A 7.5 kg cannon ball leaves a canon with a speed of 185 m/s. Find the average net force applied to the ball if the cannon muzzle

Ksju [112]

Thhhhhhhhhhhhhhhhhhhhhhhhheeeeeeeeeeeeeeee answer is 1.56

8 0

3 years ago

Read 2 more answers

You ran a power plant what could you do to make this generator produce electricity

DIA [1.3K]

You could use a magnetic generator or you could use hydraulic power

8 0

3 years ago

kumpel [21]

Answer:

Movement Time

explanation:

5 0

3 years ago