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saw5 [17]
3 years ago
14

Which describes what an outside observer at rest would observe about a spaceship that speeds up and approaches the speed of ligh

t?
Time moves faster on the spaceship, and the length of the spaceship decreases. Time moves faster on the spaceship, and the length of the spaceship increases. Time moves more slowly on the spaceship, and the length of the spaceship decreases.
Time moves more slowly on the spaceship, and the length of the spaceship increases.
Physics
2 answers:
Rzqust [24]3 years ago
7 0

Answer:

The correct answer choice is C.  

"Time moves more slowly on the spaceship, and the length of the spaceship decreases."

Explanation:

Answer on Q'let

Art [367]3 years ago
6 0
The outside observer, at rest relative to the spaceship, would see the spaceship
get shorter. and the clocks on the spaceship run slower than they should.

At the same time, the crew of the spaceship, looking back at the observer on
Earth, would see the observer on Earth get shorter, and the observer's clock
run slower than it should.

They would both be measuring what they see correctly.
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A fire breaks out and increases the Kelvin temperature of a cylinder of compressed gas by a factor of 2.4. What is the final pre
kherson [118]

Answer:

P(final) is 2.4 times P(initial).

Explanation:

Here we can assume that the cylinder did not break and it's volume and number of moles of gas present in the cylinder remains constant.

Given the temperature increases by a factor of 2.4. Let us assume that the initial temperature be T_{1} and the final temperature be T_{2}.

Given that T_{2}=2.4\times T_{1}

Now we know the ideal gas equation is PV=nRT

here V=constant , n=constant , R=gas constant(which is constant).

\frac{P}{T}=constant

\frac{P_{1} }{T_{1}}=\frac{P_{2} }{T_{2} }

P_{2}=(\frac{T_{2} }{T_{1} } )P_{1}

P_{2}=(\frac{2.4T_{1} }{T_{1} } )P_{1}

P_{2}=2.4\times P_{1}

7 0
3 years ago
Bob and John are pulling in different directions. If Bob is pulling to the right with a force of 10N, and John is pulling to the
Murljashka [212]

Answer:

The net force on the box is 2 N to the left.

The box will move to the left.

The acceleration on the box is 0.5 m/s^2 to the left.

Explanation:

Let's say movement to the right is positive and left is negative.

Bob: +10 N

John: -12 N

Add those together and you get a net force of -2 N, and the negative sign means that the box is moving to the left.

For the acceleration:

Fnet = ma

-2 = (4 kg)a

a = -0.5 m/s^2

Again, the negative sign in this answer means the box is being accelerated to the left.

4 0
3 years ago
Two long, straight parallel wires are placed 38 cm apart, one above the other. The top and bottom wires are carrying currents 4.
ElenaW [278]

Answer:

The force per unit length (N/m) on the top wire is 16.842 N/m

Explanation:

Given;

distance between the two parallel wire, d = 38 cm = 0.38 m

current in the first wire, I₁ = 4.0 kA

current in the second wire, I₂ = 8.0 kA

Force per unit length, between two parallel wires is given as;

\frac{F}{L} = \frac{\mu_oI_1I_2 }{2\pi d }

where;

μ₀ is constant = 4π x 10⁻⁷ T.m/A

Substitute the given values in the above equation and calculate the force per unit length

\frac{F}{L} = \frac{\mu_oI_1I_2 }{2\pi d } = \frac{4\pi *10^{-7}*4000*8000 }{2\pi *0.38} = 16.842 \ N/m

Therefore, the force per unit length (N/m) on the top wire is 16.842 N/m

4 0
3 years ago
Which one of the following accurately describes the force of gravity?
Aloiza [94]
B. The gravity acceleration is in the same direction as the force of gravity, and thus towards the centre of the earth

4 0
3 years ago
Janelle is exploring the relationship between the brightness of a light bulb and the current that powers it. When applying these
Vlada [557]

Answer:B

Explanation:

Y is the brightest bulb

7 0
3 years ago
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