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loris [4]
3 years ago
12

Which relations below regarding magnetic field and electric field lines are true? 1. Magnetic field lines never begin nor end bu

t always loop around on themselves while electric field lines begin at positive charges and end at negative charges. 2. Magnetic field lines never begin nor end but always loop around on themselves while electric field lines begin at negative charges and end at positive charges. 3. Magnetic field lines begin at north poles and end at south poles while electric field lines loop around on themselves. 4. Magnetic field lines begin at south poles and end at north poles while electric field lines loop around on themselves. 5. Magnetic field lines come out of north poles outside the magnet and into north poles inside the magnet. Magnetic field lines go into south poles outside the magnet and out of south poles inside the magnet. Electric field lines begin at positive charges and end at negative charges.
Physics
1 answer:
Vlad1618 [11]3 years ago
3 0

Answer:

Options 1 and 5 are correct

Explanation:

Magnetic field lines can never cross, the field is unique at any point in space. Magnetic field lines are continuous, forming closed loops without beginning or end. They go from the north pole to the south pole.

Magnetic field lines form closed loops but do not intersect.

Electric field lines originate at the positive charges and terminate at the negative charges. They move in a straight line and are parallel. Electric field lines neither form closed loops nor intersect.

Since, magnetic field lines form closed loops and move from North to South pole, they come out of north poles outside the magnet and into north poles inside the magnet, they also go into south poles outside the magnet and out of south poles inside the magnet.

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<u>The answer is not contained detail explanation, just a solution and the required values. </u>

All the details are in the pictures, the answers are marked with orange colour.

Note,

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in the task no 21:

m₁ - the mass of the copper ball; m₂ - the mass of the copper calorimeter; m₃ - the mass of the water; t₀ - the initial temperature of water in the copper calorimeter; θ - the final temperature in the calorimeter after the copper ball is transferred into a copper calorimeter; t₁ - the required initial temperature of the copper ball before it is transferred into the calorimeter.

7 0
3 years ago
How high does Pete lift his sledge hammer if he used a force of 25N to lift the hammer while doing 50J of work?
sasho [114]

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stellarik [79]

Answer:

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(b) The entropy change of the gas is, 73.0709 J/K

(c) The entropy change of the gas is equal to zero.

Explanation:

(a) The expression used for work done in reversible isothermal expansion will be,

where,

w = work done = ?

n = number of moles of gas  = 4 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = 240 K

= initial volume of gas  =  

= final volume of gas  =  

Now put all the given values in the above formula, we get:

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(b) Now we have to calculate the entropy change of the gas.

As per first law of thermodynamic,

where,

= internal energy

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As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

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As we know that, in adiabatic process there is no heat exchange between the system and surroundings. That means, q = constant = 0

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Explanation:

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