Question 6 of 10

Steam enters an adiabatic turbine at 6 MPa, 600 ℃, and 80 m/s and leaves at 50 kPa, 100 ℃, and 140 m/s. If the power output of t

lisabon 2012 [21]

Answer:

W(r,out) = 5.81 MW

$\eta$ = 86.1 %

Explanation:

we use here steam table for get value of h1, s1 etc

so use for 6MPa and 600 degree

Enthalphy of steam h1 = 3658.8 kJ/kg

Entropy of steam s 1 is = 7.1693 kJ /kg.K

and

for 50 kPa and 100 degree

Enthalphy of steam h2 = 2682.4 kJ/kg

Entropy of steam s2 is = 7.6953 kJ /kg.K

so we use here energy balance equation that is

$m\times(h1 + \frac{v1^2}{2} = m\times(h2 + \frac{v2^2}{2} + W(out)$ ..............1

put here value and we get m

m = $\frac{5\times1000}{3658.8-2682.4+\frac{80^2-140^2}{2}\times \frac{1}{1000}}$

solve it we get

m = 5.156 kg/s

so by energy balance equation

m $\psi$ 1 = m $\psi$ 2 + W(r,out)

W(r,out) = m( $\psi$ 1 - $\psi$ 2)

W(r,out) = h1 - h2 + ΔKE + ΔPE - To(s1-s2)

W(r,out) = $m[h1-h2+ \frac{v1^2-v^2}{2}- To (s1-s2)$

W(r,out) = W(a,out) - m.To.(s1-s2) ........................2

put here value

W(r,out) = 5000 - ( 5.156 × (25 + 273) ×( 7.1693 - 7.6953)

W(r,out) = 5908.19 = 5.81 MW

and

second law deficiency is

$\eta$ = $\frac{W(a,out)}{W(r,out)}$ ..............................3

put here value

$\eta$ = \frac{5}{5.81}

$\eta$ = 86.1 %

6 0

3 years ago

Show that f(v)dv = 1 ,where f(v) is the maxwell boltzmann distribution equation

sveta [45]

Answer:

rearrange the equation

Explanation:

4 0

2 years ago

Describe how a shovel makes moving dirt easier. Use the words “resistant force,” “effort force,” and “distance.” Tell what kind

timurjin [86]

A simple machine is a device for doing work that has only one part. Simple machines redirect or change the size of forces, allowing people to do work with less muscle effort and greater speed, thus making their work easier. There are six kinds of simple machines: the lever, the pulley, the wheel and axle, the inclined plane, the wedge, and the screw.

4 0

4 years ago

Read 2 more answers

PLEASE HELP ME

Ipatiy [6.2K]

Answer:

the time period is 22.63 years

Explanation:

The computation of the number of years taken is as follows:

According to the Keplers law

$T^2 \propto R^3$

Here T denotes the time period

And, R denotes the average distance among the sun and planet

Now let us assume for earth

R_1 & T_1 be 1 year

So, for Planet

$R_2 = 8R_1 , T_2 = ?$

Now applied Keplers law

$(\frac{T_2}{T_1})^2 \propto (\frac{R_2}{R_1})^3\\\\(T_2)^2 = (\frac{8R_1}{R_1})^3 \times 1^2\\\\(T_2)^2 = 512\\\\T_2 = 22.674$

So, the time period is 22.63 years

8 0

3 years ago

a ball drops some distance and loses 30 j of gravitational potential energy. do not ignore air resistance. how much kinetic ener

aniked [119]

Thus, more than 30 J of potential energy can be loosed by the ball. Thus, the gravitational potential energy of the ball is more than 30 J.

If there is no air resistance, the ball's potential energy is entirely transformed into kinetic energy. When air resistance is taken into account, a portion of the potential energy is used to overcome it. Thus, AU > AKE. In the current scenario, a ball gains 30 J of kinetic energy while falling and is treated as encountering air resistance. The energy that an object retains due to its position in relation to other objects, internal stresses, electric charge, or other factors is known as potential energy in physics. The potential energy will be transformed into kinetic energy if the stones fall. High on the tree, branches have the potential to fall, which gives them energy. Chemical potential energy exists in the food we eat.

Learn more about potential energy here:

brainly.com/question/24284560

#SPJ4

5 0

1 year ago