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vazorg [7]
3 years ago
14

Class material don't interact please

Chemistry
1 answer:
bagirrra123 [75]3 years ago
8 0

A 0.00143 M  concentration of MnO4^- is not a reasonable solution .

<h3>Number of moles of carbonate</h3>

The ions left in solution are Na^+ and NO3^-

Number of moles of calcium nitrate  = 100/1000 L × 1 = 0.1 moles

Since;

1 mole of sodium carbonate reacts with 1 mole of calcium nitrate  then 0.1 moles of sodium carbonate were used.

<h3>Conductivity of filtrate</h3>

The claim of the student that the concentration of sodium carbonate is too low is wrong because the value was calculated from concentration  and volume of calcium nitrate  and not using the precipitate. If the filtrate is tested for conductivity, it will be found to conduct electricity because it contains sodium and NO3 ions.

2) In the reaction as shown, the MnO4^- ion was reduced.

The initial volume is 3.4 mL while the final volume is 29.6 mL.

Number of moles of MnO4^- ion = (29.6 mL - 3.4 mL)/1000 × 0.0235 M = 0.0006157 moles

<h3>The calculations are performed as follows</h3>

  • If 2 moles of MnO4^- reacted with 5 moles of acid

0.0006157 moles of MnO4^- reacted with  0.0006157 moles ×  5 moles/ 2 moles

= 0.0015 moles

  • In this case, number of moles of acid = 0.139 g/90 g/mol = 0.0015 moles

Number of moles of MnO4^-  = 0.00143 M × (29.6 mL - 3.4 mL)/1000

= 0.000037 moles

  • If 2 moles of MnO4^- reacts with 5 moles of acid

0.000037 moles of MnO4^- reacts with 0.000037 moles × 5 moles/ 2 moles

= 0.000093 moles

  • Hence, this is not a reasonable amount of solution.

Learn more about MnO4^- : brainly.com/question/10887629

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Answer:

Mole Fraction (H₂O)  =  0.6303

Mole Fraction (C₂H₅OH)  =  0.3697

Explanation:

(Step 1)

Calculate the mole value of each substance using their molar masses.

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

200.0 g H₂O            1 mole
---------------------  x  ------------------  =  11.10 moles H₂O
                                 18.014 g

Molar Mass (C₂H₅OH): 2(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol

Molar Mass (C₂H₅OH): 46.068 g/mol

300.0 g C₂H₅OH              1 mole
----------------------------  x  --------------------  =  6.512 moles C₂H₅OH
                                         46.068 g

(Step 2)

Using the mole fraction ratio, calculate the mole fraction of each substance.

                                            moles solute
Mole Fraction  =  ------------------------------------------------
                               moles solute + moles solvent

                                                  11.10 moles H₂O
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (H₂O)  =  0.6303

                                             6.512 moles C₂H₅OH
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (C₂H₅OH)  =  0.3697

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