Answer:

Explanation:
The equation for force is given:

First, we must find the total mass, which is the sum of the boy's mass and the go-cart's mass.
- total mass= boy's mass + go cart's mass
The boy's mass is 35 kilograms and the go cart's is 65 kilograms.
- total mass= 35 kg+ 65 kg=100 kg
Now we know the total mass and the acceleration.

Substitute the values into the formula.

Multiply.

- 1 kilograms meter per square second is equal to 1 Newton.
- Our answer of 500 kg*m/s² is equal to 500 Newtons.

The force exerted by the go cart engine is <u>500 Newtons.</u>
The vertical component of the force exerted by the hi.nge on the beam is 114.77 N.
<h3>Tension in the cable</h3>
Apply the principle of moment and calculate the tension in the cable;
Clockwise torque = TL sinθ
Anticlockwise torque = ¹/₂WL
TL sinθ = ¹/₂WL
T sinθ = ¹/₂W
T = (W)/(2 sinθ)
T = (29 x 9.8)/(2 x sin57)
T = 169.43 N
<h3>Vertical component of the force</h3>
T + F = W
F = W - T
F = (9.8 x 29) - 169.43
F = 114.77 N
Thus, the vertical component of the force exerted by the hi.nge on the beam is 114.77 N.
Learn more about tension here: brainly.com/question/24994188
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Given:-
- Mass of the cart (m) = 35 kg
- Speed (consider Velocity) = 1.2 m/s
To Find: Momentum of the cart.
We know,
p = mv
where,
- p = Momentum,
- m = Mass &
- v = Velocity.
Thus,
p = (35 kg)(1.2 m/s)
→ p = 42 kg m/s (Ans.)
Conclusion:-
A. ☑️ 42 kilogram - metre per second.
Answer:
A. a rigorously tested explanation
Explanation:
- B. and D. are out - theories are not opinionated, they are factual
- C. is out - not all theories are mathematical
- A. is the best choice
Answer:
Electromagnetic wave are waves formed as a result of the oscillatory activities involving the electric and the magnetic field.
However in an Electromagnetic wave, the electric field and magnetic field carry equal amounts of energy and the magnitude of the electric field is directly proportional to the magnitude of the magnetic field. This direct proportionality gives rise to the speed of light being the constant between the two fields.
When the electric field is doubled then an equal action is to be set for the magnetic field so it doesn’t deviate from its main functions and characteristics.