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ycow [4]
3 years ago
10

The diagrams show objects’ gravitational pull toward each other. Which statement describes the relationship between diagram X an

d Y?
A. Gravity attracts only larger objects toward one another.
B. Gravity attracts larger objects only if they are close to one another.
C.If the masses of the objects increase, then the force between them also increases.
D.If distance between the objects increases, then the amount of force also increases.
Physics
2 answers:
creativ13 [48]3 years ago
8 0

' C ' is the only correct statement on the list.  We don't know anything about diagram-x or diagram-y because we can't see them.

Nookie1986 [14]3 years ago
7 0

The answer is c on edugentiy hope this helped

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A pulley system is such that a person pulls down with 10 N of force to lift a 20 N object. The
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Examples of structure or machine parts that may fail due to bending​
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<em>Structural failure is initiated when a material is stressed beyond its strength limit, causing fracture or excessive deformations; one limit state that must be accounted for in structural design is ultimate failure strength.</em><em><u>Compressive, tensile, bending and buckling are the basic types of structural failure for construction elements. These are caused due to faults in design and construction</u></em>

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A ball, initially at rest, reaches a speed of 20 m/s at the bottom of the apparatus. If it takes the ball 10 seconds to reach th
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Answer:

2 m/s²

Explanation:

Given:

v₀ = 0 m/s

v = 20 m/s

t = 10 s

Find: a

a = (v − v₀) / t

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3 0
3 years ago
Consider two planets of mass m and 2m,
Rzqust [24]

Answer:

Part a)

\frac{F_1}{F_2} = 10.125

Part b)

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

\frac{T_1}{T_2} = 9.54

Explanation:

Part a)

As we know that the gravitational force is given as

F = \frac{GMm}{r^2}

so we will have to find the ratio of force on two planets due to star

so here we have

\frac{F_1}{F_2} = \frac{m_1r_2^2}{m_2r_1^2}

\frac{F_1}{F_2} = \frac{m (4.5r)^2}{(2m) r}

\frac{F_1}{F_2} = 10.125

Part b)

Orbital speed is given as

v = \sqrt{\frac{GM}{r}}

so the ratio of two orbital speed is given as

\frac{v_1}{v_2} = \frac{r_2}{r_1}

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

Time period is given as

T = 2\pi\sqrt{\frac{r^3}{GM}}

so the ratio of two time period is given as

\frac{T_1}{T_2} = \sqrt{\frac{r_1^3}{r_2^3}}

\frac{T_1}{T_2} = \sqrt{\frac{4.5r^3}{r^3}}

\frac{T_1}{T_2} = 9.54

8 0
3 years ago
Read 2 more answers
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