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zimovet [89]
3 years ago
9

Which is an example of transfroming potential energy to kinetic​

Physics
2 answers:
poizon [28]3 years ago
8 0

Answer:

A ball dropped to ground

Explanation:

Rudik [331]3 years ago
6 0

Answer:

A ball being dropped to the ground

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What kind of tectonic plate boundary must have existed in the past where copper deposits are found, based on the way they are fo
Maksim231197 [3]

Answer:

older plates that are subducting almost perpendicularly, and when the location is far away from the edge of other tectonic plates, are the most likely areas for copper deposits to form

Explanation:

5 0
3 years ago
Consider an e. coli to be a cylinder with a diameter of 1 micrometer (um) and with a length of 2 micrometer (um).
julia-pushkina [17]

Answer:

A=6.28\ \mu m^2

Part 1

V=1.57 \ \mu m^3

Part 2

A=6.28\ \mu m^2

Explanation:

Given that

Diameter,d=1 μm

Length ,l=2 μm

As we know that volume of cylinder given as

V=\pi r^2l

V=\pi \times 0.5^2\times 2 \ \mu m^3

V=1.57 \ \mu m^3

Surface area,A

A=π d l

A=\pi \times 1 \times 2\ \mu m^2

A=6.28\ \mu m^2

Part 1

V=1.57 \ \mu m^3

Part 2

A=6.28\ \mu m^2

4 0
3 years ago
What muscles do you use to throw a ball
tamaranim1 [39]
You use your shoulder muscles aka the deltiods of the muscle which plays a huge part in the rotation of your arm 
you also use your triseps 
also, latissimus dorsi 
abdominals 
and your quadriceps 

8 0
2 years ago
Dois carros, a e b, móveis se em uma estrada retilínea com volocidade constante,vª =20m/s e v=18 m/s , respectivamente. O carro
aalyn [17]

Answer:

t = 250 s = 4.167 s

Explanation:

Carro A

x = x₀+v*t

⇒  x = 0 + 20*t  

⇒  x = 20*t   <em>(i)</em>

Carro B

x = x₀+v*t

⇒  x = 500 + 18*t    <em>(ii)</em>

Se as equações são as mesmas, verifica-se  <em>(i) = (ii)</em>

20*t = 500 + 18*t

⇒  20*t - 18*t = 500

⇒  2*t = 500

⇒  t = 250 s = 4.167 s

6 0
3 years ago
1.48 Assume that the air volume in a small automobile tire is constant and equal to the volume between two concentric cylinders
ICE Princess25 [194]

Answer:

a) 0.018 kg

b) 262 kPa

Explanation:

The volume of the concentric cylinders would be:

V = π/4 * h * (D^2 - d^2)

V = π/4 * 13 * (52^2 - 33^2) = 16500 cm^3 = 0.0165 m^3

The state equation of gases:

p * V = m * R * T

Rearranging:

m = (p * V) / (R * T)

R is 287 J/(kg * K) for air

25 C = 298 K

m0 = 202000 * 0.0165 / (287 * 298) = 0.039 kg

After pumping more air the volume remains about the same, but temperature and pressure change.

30 C = 303 K

m1 = 303000 * 0.0165 / (287 * 303) = 0.057 kg

The mass that was added is

m1 - m0 = 0.057 - 0.039 = 0.018 kg

If that air is cooled to 0 C

0 C  is 273 K

p = m * R * T / V

p = 0.057 * 278 * 273 / 0.0165 = 262000 Pa = 262 kPa

3 0
3 years ago
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