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arlik [135]
3 years ago
12

Two charged particles exert an electric force of 27 N on each other. What will the magnitude of the force be if the distance bet

ween the particles is reduced to one-third of the original separation
Physics
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

243 N

Explanation:

The formula for electromagnetic force is F= Kq1q2/r^2

where r is the distance between the charges, if the distance between the charges is reduced by 1/3 then F will increase by 9 [(1/3r)^2 becomes 1/9r which is 9F] so 27*9 is 243N

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An airplane has a speed of 135 mi/h in still air. It is flying straight north so that it is always directly above a north-south
vlabodo [156]

Answer:

The answer is below

Explanation:

Let vₐ be the speed of airplane = 135 mph, vₙ be the speed of the wind = 70 mph and vₐₙ be the speed of the airplane relative to the wind.

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a) The direction of the wind is 75° in the south east direction while the airplane is heading 30° in the north east direction.

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