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arlik [135]
3 years ago
12

Two charged particles exert an electric force of 27 N on each other. What will the magnitude of the force be if the distance bet

ween the particles is reduced to one-third of the original separation
Physics
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

243 N

Explanation:

The formula for electromagnetic force is F= Kq1q2/r^2

where r is the distance between the charges, if the distance between the charges is reduced by 1/3 then F will increase by 9 [(1/3r)^2 becomes 1/9r which is 9F] so 27*9 is 243N

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Six seconds after starting from rest, a car is moving at 15 m/s. What is the car's
Sidana [21]

Answer:

  2.5 m/s²

Explanation:

a = ∆v/∆t = (15 m/s)/(6 s) = (15/6) m/s² = 2.5 m/s²

7 0
3 years ago
5. A stream of air at 12 bar and 900 K is mixed with another stream of air at 2 bar and 400 K with 2 times the mass flowrate. If
Softa [21]

Answer:

The anserrs to the question are

(a)  The temperature would be 566.67  K and

(b) The pressure of the resulting air stream is 14 bar

Explanation:

Here the two streams of gases meet ad form a single stream

The steady-flow energy equation can be implemented at the mixing point of the to streams as follows

mₐhₐ₁ + mₙ hₙ₁ + Q° + W° = mₐhₐ₂ + mₙhₙ₂

Where the flow is adiabatic, we have

Q = 0 and  W = 0  hence

mₐhₐ₁ + mₙ hₙ₁ = mₐhₐ₂ + mₙhₙ₂ where h = cp×T we have

mₐcpₐ×Tₐ + mₙcpₙ×Tₙ  = mₐcpₐ×T + mₐcpₙ×T

Therefore the final temperature T is given by

T = \frac{m_ac_{pa}T_a + m_nc_{pn}T_n}{m_ac_{pa} + m_nc_{pn}}  for the same kind of gas cpₐ =cpₙ therefore

T = \frac{m_aT_a + m_nT_n}{m_a + m_n} where mₐ and mₙ are mass flow rate

Therefore we have where Tₐ = = 900 K and Tₙ = 400 K and mₙ = 2mₐ gives

T = \frac{m_a*900 + 2*m_a*400}{m_a + 2*m_a} = T = \frac{900 + 800}{1 + 2} = 1700/3 = 566.67 K  

From Dalton's law, the total pressure of a mixture of gases is equal to the sum of the partial pressures of the components of the mixture

Therefore the total pressure of the combined stream = pₐ + pₙ = p

= 12 bar + 2 bar = 14 bar

Stream pressure = 14 bar

4 0
3 years ago
A 1.0-kg cue ball traveling at 15 m/s strikes a stationary billiard ball of mass 1.5 kg. After the collision, the cue ball remai
Igoryamba

Answer:

Other ball's velocity is 10 m/s

Explanation:

We can use conservation of momentum:

P_{1i} +P_{2i} =P_{1i} +P_{2i}\\1 * 15 + 1.5 * 0 = 1 * 0 + 1.5 * v\\15 = 1.5 * v\\v=\frac{15}{1.5} \,\frac{m}{s} \\v=10 \,\frac{m}{s}

8 0
3 years ago
Determine the minimum angle at which a roadbedshould be banked
poizon [28]

To solve this problem, apply the concepts related to the relationship given between the centripetal Force and the Weight.

The horizontal force component is equivalent to the weight of the car, while the vertical component is linked to the centripetal force exerted on the car, therefore,

T cos\theta = mg \rightarrow T = \frac{mg}{cos\theta}

Tsin\theta = \frac{mv^2}{r} \rightarrow T = \frac{mv^2/r}{sin\theta}

Equating both equation we have that,

\frac{mv^2}{r} = mgtan\theta

tan\theta = \frac{v^2}{rg}

Rearranging to find the angle we have that,

\theta = tan^{-1} (\frac{v^2}{rg})

Our values are given as,

r = 2.00*10^2m

v = 20m/s

\theta = tan^{-1}(\frac{20^2}{(2*10^{2})(9.8)})

\theta = 11.53 \°

Therefore the minimum angle will be 11.53°

5 0
3 years ago
An airplane flies with a constant speed of
mafiozo [28]
The airplane is traveling 620mph, or 620m/60 minutes

Divide 270 by 60 to find the number of hours the plane is flying.
270/60 = 4.5

The plane will fly for 4.5 hours. Speed * time = Distance (make sure units are the same)
620mph*4.5hr = 2,790 miles
5 0
3 years ago
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