We have the equation of motion $s = ut + \frac{1}{2} at^2$ , where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.

Here s = 300 m, u = 0 m/s, a = 9.81 $m/s^2$

Substituting

$300 = 0*t+\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2 = 300\\ \\ t =7.82 seconds$

Now we have v = u+at, where v is the final velocity

Here u = 0 m/s, a= 9.81 $m/s^2$ and t = 7.82 seconds

Substituting

v = 0+9.8*7.82 = 76.68 m/s

The speed with which the penny strikes the ground = 76.68 m/s.

3 0

3 years ago

PLEASE HELP ME!!!

klasskru [66]

1.velocity and acceleration

3.inertia

5.speed

4 0

3 years ago

2 Which is true of a parallel circuit?

mars1129 [50]

Answer:

fxb

Explanation:bfffffffff

8 0

3 years ago

How does the flatter design make sweeping the floor easier

Ratling [72]

Answer:

there will be no cracks so the trash won't get stuck

5 0

3 years ago