Answer:
The electric field is 
Explanation:
Given that,
Radius = 2.00 cm
Number of turns per unit length 
Current 
We need to calculate the induced emf
Where, n = number of turns per unit length
A = area of cross section
=rate of current
Formula of electric field is defined as,
Where, r = radius
Put the value of emf in equation (I)
....(II)
We need to calculate the rate of current
....(III)
On differentiating equation (III)
Now, put the value of rate of current in equation (II)
Hence, The electric field is
The hiker followed the north trail a distance of two kilometers in thirty minutes is an example that provides a complete scientific description of an object in motion.
The answer would be D) The tropical convection region because the states below SC are all tropical and the current would go up to SC. I hope this helps.
Answer:
129.74 Hz
Explanation:
Given:
Wave velocity ( v ) = 346 m / sec
wavelength ( λ ) = 2.69 m
We have to calculate Frequency ( f ) :
We know:
v = λ / t [ f = 1 / t ]
v = λ f
= > f = v / λ
Putting values here we get:
= > f = 346 / 2.69 Hz
= > f = 34600 / 269 Hz
= > f = 129.74 Hz
Hence, frequency of sound is 129.74 Hz.
Answer:
the magnitude of the average contact force exerted on the leg is 3466.98 N
Explanation:
Given the data in the question;
Initial velocity of hand v₀ = 5.25 m/s
final velocity of hand v = 0 m/s
time interval t = 2.65 ms = 0.00265 s
mass of hand m = 1.75 kg
We calculate force on the hand F
using equation for impulse in momentum
F × t = m( v - v₀ )
we substitute
F × 0.00265 = 1.75( 0 - 5.25 )
F × 0.00265 = 1.75( - 5.25 )
F × 0.00265 = -9.1875
F = -9.1875 / 0.00265
F = -3466.98 N
Next we determine force on the leg F
Using Newton's third law of motion
for every action, there is an equal opposite reaction;
so, F = - F
we substitute
F = - ( -3466.98 N )
F = 3466.98 N
Therefore, the magnitude of the average contact force exerted on the leg is 3466.98 N
