Answer:
x-component=-9.3 m
Magnitude of A=17.7m
Explanation:
We are given that


We have to find the x-component of A and magnitude of A.
According to question

Substitute the values then we get


m




The value of x-component of A is negative because the vector A lie in second quadrant.
Hence, the x- component of A=-9.3 m
Answer:
A heat engine is a device that converts internal energy into work. Internal energy is increased by the addition of heat. The efficiency of a heat engine is a measurement of how efficiently it works. Efficiency compares the amount of useful energy extracted from a process to the total energy input. The heat engine will be more efficient if the percentage is higher.
Explanation:
We need to charge a metal sphere positively without touching it. This can be achieved using electrostatic induction.
As we know that here gun + bullet system is isolated from all other external force system
so here the momentum of system is always conserved
so we will say

here we know that




now we will have

by solving above equation we will have

Answer: Its applied force and friction, The friction is the drag and the applied force is you pushing