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3 years ago

Why the bicycle stops when the cyclist stops pedaling?

2 answers:

5 0

There is no kintentic energy being giving to the bike through the action of pedaling therefore the bike will stop moving

mr_godi [17]3 years ago

3 0

Answer:

The bicycle slows down because of the frictional force acting on the tyres of the bicycle. When this frictional force overcomes the force applied by paddling, the bicycle stops.

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A exercise ball is on a table 2.5 m above the ground. What is the mass

horsena [70]

Answer:

2.27kg

Explanation:

The Potential energy gained = Force gravity× Height

Force gravity on the ball is GPE/ height

56.8/2.5=22.72N

the mass = 22.72/10= 2.27kg

4 0

3 years ago

The change of motion of an object depends on ___

Gennadij [26K]

A is the answer mass and force

3 0

2 years ago

3. If you had parental units of RR and Rr (R being dominant round and r being recessive

yanalaym [24]

C all round

Explanation:

because the outcome of a the traits would be RR, RR, Rr, Rr so it would be all round if it was Rr and Rr than there would have RR, Rr, Rr, and rr and that would have been a

7 0

2 years ago

What does displacement depend on

bogdanovich [222]

The answer to this question is distance.

7 0

3 years ago

An object with mass 3M is launched straight up. When it reaches its maximum height, a small explosion breaks the object into two

german

Answer:

$x_{L} = 106\,m$

Explanation:

Each piece is analyzed by using the Principle of Momentum Conservation and the Impulse Theorem:

Heavier object:

$(2\cdot M)\cdot (0) + F\cdot \Delta t = (2\cdot M)\cdot v_{H}$

Lighter object:

$M\cdot (0) + F\cdot \Delta t = M\cdot v_{L}$

After the some algebraic handling, the following relationship is found:

$M\cdot v_{L} = 2\cdot M\cdot v_{H}$

$v_{L} = 2\cdot v_{H}$

Given that both pieces have horizontal velocities only and both are modelled as projectiles, the horizontal component of velocity remains constant and directly proportional to travelled distance. Then:

$\frac{v_{L}}{v_{H}} = \frac{x_{L}}{53\,m}$

$2 = \frac{x_{L}}{53\,m}$

$x_{L} = 106\,m$

8 0

3 years ago