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shusha [124]
3 years ago
15

10 PTS!

Physics
2 answers:
spin [16.1K]3 years ago
5 0
" This manual applies to Compact Liquid <span>Fuel Pumps & </span>Dispensers<span> The </span>liquid pressure<span> range is from 0.5 - 20m These totals </span>can<span> be displayed by </span>pressing<span> the CLEAR </span>button<span> on the preset keypad five times in When connecting to sites </span>powered<span> by. "</span>
konstantin123 [22]3 years ago
5 0
(Remeber as force increases, pressure increases.)
When you push the button, the pressure of the liquid inside the dispenser increases. Hence, the more force you apply to the button, the more quickly the liquid will eject. 

~Hope this helped! Gl~
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A charge partides round a 1 m radius circular particle accelerator at nearly the speed of light. Find : (a) The period (b) The c
Scrat [10]

Explanation:

It is given that,

Radius of circular particle accelerator, r = 1 m

The distance covered by the particle is equal to the circumference of the circular path, d = 2πr

d = 2π × 1 m

(a) The speed of satellite is given by total distance divided by total time taken as :

speed=\dfrac{distance}{time}

Let t is the period of the particle.

t=\dfrac{d}{s}

d = distance covered

s = speed of particle

It is given that the charged particle is moving nearly with the speed of light

t=\dfrac{d}{c}

t=\dfrac{2\pi\times 1\ m}{3\times 10^8\ m/s}

t=2.09\times 10^{-8}\ s

(b) On the circular path, the centripetal acceleration is given by :

a=\dfrac{c^2}{r}

a=\dfrac{(3\times 10^8\ m/s)^2}{1\ m}

a=9\times 10^{16}\ m/s^2

Hence, this is the required solution.

8 0
3 years ago
What is the speed of a wave with a wavelength of 10 mm and a frequency of 5.0 Hz?
sleet_krkn [62]
Speed = wavelength × frequency
speed = 10/1000 × 5.0
speed = 0.001 × 5.0
speed = 0.005m/s
4 0
3 years ago
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What is the function or the skeletal system hdbdb
yKpoI14uk [10]

Explanation:

Hope its helps u

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How many days of a diet of 1910 large calories are equivalent to the gravitational energy change from sea level to the top of Mo
andreyandreev [35.5K]

Answer:

0.58 days is needed

Explanation:

Gravitational energy change from a height change equal to 8848 m for a mass of 53 kg is:

m*g*h = 53*9.81*8848 = 4600340.64 J = 4600.34 kJ

4.184 kJ are equivalent to 1 kcal, then:

4.184 kJ / 4600.34 kJ = 1 kcal / x kcal

x = 4600.34/4.184

x = 1099.5 kcal or large calories

The diet is 1910 kcal/day, then you need 1099.5/1910 = 0.58 days

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3 years ago
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inna [77]
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