Answer:
t = 23.255 s, x = 2298.98 m, v_y = - 227.90 m / s
Explanation:
After reading your extensive writing, we are going to solve the approach.
The initial speed of the plane is 250 miles / h and it is at an altitude of 2650 m; In general, planes fly horizontally for launch, therefore this is the initial horizontal speed.
As there is a mixture of units in different systems we are going to reduce everything to the SI system.
v₀ₓ = 250 miles h (1609.34 m / 1 mile) (1 h / 3600 s) = 111.76 m / s
y₀ = 2650 m
Let's set a reference system with the x-axis parallel to the ground, the y-axis is vertical. As time is a scalar it is the same for vertical and horizontal movement
Y axis
y = y₀ + v₀ t - ½ g t²
the initial vertical velocity when the cargo is dropped is zero and when it reaches the floor the height is zero
0 = y₀ + 0 - ½ g t²
t = 
t = √(2 2650/ 9.8)
t = 23.255 s
Therefore, for the cargo to reach the desired point, it must be launched from a distance of
x = v₀ₓ t
x = 111.76 23.255
x = 2298.98 m
at the point and arrival the speed is
vₓ = v₀ₓ = 111.76
vertical speed is
v_y = v_{oy} - gt
v_y = 0 - gt
v_y = - 9.8 23.25 555
v_y = - 227.90 m / s
the negative sign indicates that the speed is down
in the attachment we have a diagram of the movement
Answer:
The final kinetic energy is 
Explanation:
From the question we are told that
The electric field is 
The charge on the object is 
The mass of the object is 
The distance moved by the object is 
The workdone on the object by the fields is mathematically represented as
![W = [qE + mg]d](https://tex.z-dn.net/?f=W%20%3D%20%20%5BqE%20%2B%20mg%5Dd)
Now this workdone is equivalent to the final kinetic energy so
![K = W = [qE + mg]d](https://tex.z-dn.net/?f=K%20%3D%20W%20%3D%20%20%5BqE%20%2B%20mg%5Dd)
substituting values
![K = W = [4.5*10^{-3 } *100 + 0.68 * 9.8]* 1](https://tex.z-dn.net/?f=K%20%3D%20W%20%3D%20%20%5B4.5%2A10%5E%7B-3%20%20%7D%20%2A100%20%20%2B%200.68%20%2A%209.8%5D%2A%201)
Answer:
The force of the nail pushing in the opposite direction
Answer:
The answer is The acceleration is double its original value.
Explanation:
<h2><u>
It is because of the second trial of accelaration. Because of this, an object's acceleration doubles from its original value.</u></h2><h2><u>
</u></h2>
Hope this helps....
Have a nice day!!!!
Answer: 
Firstly we have to draw the Free Body Diagram (FBD) as shown in the figure attached.
Where the weight 
of the block has an x-component and y-component:
(1)
(2)
As well as the Normal Force 
:
(3)
(4)
In addition, we know 
, then 
In the X-component:
(5)
Substituting (1) in (5):
(6)
In addition, we know 
, where 
is the mass of the block and 
the gravity acceleration, which is equal to 
So:
(7)
(8)
(9) >>>>This is the acceleration of the block
On the other hand, we have the following equation that expresses a <u>relation between</u> the distance 
with the acceleration 
and time 
:
(10)
We already know the value of and calculated , we have to find :
(11)
(12)
(13) >>>This is the time it takes to the block to go from the initial velocity 
to its final velocity 
If the acceleration is the variation of the velocity in time, we can use the following equation to find :
(13)
If 
(14)
(15)
Finally we get the value of the Final Velocity of the block:
