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ddd [48]
2 years ago
11

How do electromagnetism and gravitation differ from the strong and weak nuclear forces?

Physics
1 answer:
katrin [286]2 years ago
5 0
Electromagnetism is the interaction between charged particles. It is very long ranged. It can manifest as a force causing like charges to repel and unlike charges to attract. ... The weak nuclear force is very short ranged and is not a force at all.
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On the way to school, Jed traveled 100m north, 300m east, 100 north, 100m east, and 100m north. A.) Find the total distance trav
Oduvanchick [21]

Answer:

Total distance = 700 m

Displacement = 500 m

Explanation:

Notice that Jed travelled a total of 3 x 100 m = 300 m in the North direction, and 300 m + 100 m = 400 m in the East direction. Therefore the total distance he travelled is:  300 + 400 = 700 m.

But the actual displacement is given by the Pythagorean theorem as the hypotenuse of a right angle triangle of legs 300 m and 400 m:

displacement = \sqrt{300^2+400^2} =\sqrt{250000} =500\,m

5 0
3 years ago
Energy caused by the flow of ocean water
Arlecino [84]
It’s thermal energy
8 0
2 years ago
What can be defined as the rate at which velocity changes
taurus [48]

Answer:

acceleration

Explanation:

The rate at which velocity changes is the definition of the physical quantity called acceleration, and it is given by the formula: a=\frac{v_f-v_i}{\Delta t}

where \Delta t is the time that took to change from the initial velocity v_i to the final velocity v_f

4 0
3 years ago
Read 2 more answers
A particle is released as part of an experiment. Its speed t seconds after release is given by v (t )equalsnegative 0.4 t square
torisob [31]

Answer:

a) 2.933 m

b) 4.534 m

Explanation:

We're given the equation

v(t) = -0.4t² + 2t

If we're to find the distance, then we'd have to integrate the velocity, since integration of velocity gives distance, just as differentiation of distance gives velocity.

See attachment for the calculations

The conclusion of the attachment will be

7.467 - 2.933 and that is 4.534 m

Thus, The distance it travels in the second 2 sec is 4.534 m

6 0
3 years ago
A car travelling at 15m/s comes to a rest in a distance of 14m when the brakes are applied. Calculate the deceleration of the ca
vlada-n [284]

Answer:

force of the breaks is 6650 N, direction opposite to direction of movement

Explanation:

6 0
3 years ago
Read 2 more answers
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