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choli [55]
3 years ago
9

Which best describes a radioactive isotope?

Physics
2 answers:
goldenfox [79]3 years ago
5 0
I think its A because t<span>he nuclei of some isotopes are unstable and emit radiation.</span>
sveta [45]3 years ago
4 0

Answer: Option (A) is the correct answer.

Explanation:

An isotope with an unstable nucleus which decomposes readily and results in the emission of radiation and a nuclear electron or helium nucleus achieves a stable nuclear composition is known as a radioactive isotope.

For example, ^{210}_{84}Po \rightarrow ^{4}_{2}He + ^{206}_{82}Pb

Here isotope of polonium decomposes in order to achieve a stable nuclear composition.

Thus, we can conclude that an atom is unstable best describes a radioactive isotope.





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A football kick returner catches the ball just as a player from the opposing team dives to tackle him. At the time of impact, th
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The total momentum of the players after collision is 130 kgm/s.

The given parameters:

  • <em>Initial momentum of the returner, </em>P_i_1<em> = 0 kgm/s</em>
  • <em>The initial momentum of the diving player, </em>P_i_2<em> = 130 kgm/s</em>

The total momentum of the players after collision is determined by applying the principle of conservation of linear momentum as follows;

P_f = P_i_1 + P_i_2\\\\P_f = 0 + 130\\\\P_f = 130 \ kgm/s

Thus, the total momentum of the players after collision is 130 kgm/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

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2 years ago
Please help on this one?
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the object distance of both lenses are positive.

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3 years ago
A horizontal clothesline is tied between 2 poles, 16 meters apart. When a mass of 3 kilograms is tied to the middle of the cloth
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Answer:

The magnitude of the tension on the ends of the clothesline is 41.85 N.

Explanation:

Given that,

Poles = 2

Distance = 16 m

Mass = 3 kg

Sags distance = 3 m

We need to calculate the angle made with vertical by mass

Using formula of angle

\tan\theta=\dfrac{8}{3}

\thta=\tan^{-1}\dfrac{8}{3}

\theta=69.44^{\circ}

We need to calculate the magnitude of the tension on the ends of the clothesline

Using formula of tension

mg=2T\cos\theta

Put the value into the formula

3\times9.8=2T\times\cos69.44

T=\dfrac{3\times9.8}{2\times\cos69.44}

T=41.85\ N  

Hence, The magnitude of the tension on the ends of the clothesline is 41.85 N.

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