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Virty [35]
2 years ago
5

I need 11-14 asap please

Mathematics
1 answer:
Olegator [25]2 years ago
3 0
11. 3(22-3y)-4y=-25
66-13y=-25
-13y=-91
Y=7
X=22-3(7)=1.
12,13,14 similar
You might be interested in
How do you solve this problem
Kryger [21]

Answer:

sin(A) = \frac{21}{{29} }

cos(A)=\frac{20}{29 }

tan(A)=\frac{21}{20}

sin(C) = \frac{20}{{29} }

cos(C)=\frac{21}{29 }

tan(C)=\frac{20}{21}

Step-by-step explanation:

So first we need to make sure we know the trig identities to solve this problem.

  • sin(\alpha )=\frac{opposite}{hypotenuse}
  • cos(\alpha )=\frac{adjacent}{hypotenuse}
  • tan(\alpha )=\frac{opposite}{adjacent}

Here we only have two legs of the triangle, so we will need to use the Pythagorean Theorem a² + b² = c² to solve for the missing leg, the hypotenuse in this case.

  • Solving for the hypotenuse, c, we get c = \sqrt{a^{2} +b^{2} }
  • Here a = 20 and b = 21, so plugging in these values to the equation we get: c= \sqrt{(20)^{2}+(21)^{2}  } =\sqrt{400+441} =\sqrt{841}=29

Now we can use the trig identities to figure out the missing values for the problem

  • sin(A) = \frac{21}{{29} }
  • cos(A)=\frac{20}{29 }
  • tan(A)=\frac{21}{20}
  • sin(C) = \frac{20}{{29} }
  • cos(C)=\frac{21}{29 }
  • tan(C)=\frac{20}{21}
4 0
2 years ago
What is the answer of 7(2 + x) = 35
lyudmila [28]

Answer:

=14+7x=35

=7x =35-14

=x =21/7

x=3

The answer is 3

Step-by-step explanation:

HOPE THIS HELPS!!!

PLEASE MARK ME AS BRAINLIEST!!

3 0
3 years ago
Read 2 more answers
The following expression is written by some students: A+B=C. if ''A'' is always twice the value of ''B''. what is the value of '
ANEK [815]

Answer:

c=3

Step-by-step explanation:

a+b=c

a is double the value of b, so if a is 2, then b is 1.

2+1=3

hope this helps!

please mark me brainliest. thanks!

6 0
2 years ago
Pls help <br><br> Evaluate. [120 + (12 ÷ 3 • 30)] ÷ 20 + 102
sleet_krkn [62]
The answer is 114. Here’s what I did.

4 0
3 years ago
Find the conjugate of the complex number, use division:<br> 2+i<br> ——<br> 1+i
Fittoniya [83]

I assume you mean divide using the conjugate to rationalize the denominator and express the result in standard rectangular form.

\dfrac{2+i}{1+i} = \dfrac{2+i}{1+i} \cdot \dfrac{1-i}{1-i} = \dfrac{2(1)-i^2-2i+i}{1^2+1^2} = \frac 3 2 - \frac 1 2 i


4 0
3 years ago
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