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taurus [48]
3 years ago
13

Suggest why there is a lid on the container.

Chemistry
1 answer:
mario62 [17]3 years ago
4 0

So what ever that is in the jar dont spill out and it be no  good thats why you keep a lid on things
You might be interested in
In a study of the formation of NOx air pollution, a chamber heated to 2200°C was filled with air (0.790 atm N₂, 0.210 atm O₂). W
Irina-Kira [14]

Answer:

N₂ = 0.7515atm

O₂ = 0.1715atm

NO = 0.0770atm

Explanation:

For the reaction:

N₂(g) + O₂(g) ⇄ 2NO(g)

Where Kp is defined as:

Kp = \frac{P_{NO}^2}{P_{N_2}P_{O_2}}}

Pressures in equilibrium are:

N₂ = 0.790atm - X

O₂ = 0.210atm - X

NO = 2X

Replacing in Kp:

0.0460 = [2X]² / [0.790atm - X] [0.210atm - X]

0.0460 = 4X² / 0.1659 - X + X²

0.0460X² - 0.0460X + 7.6314x10⁻³ = 4X²

-3.954X² - 0.0460X + 7.6314x10⁻³ = 0

Solving for X:

X = - 0.050 → False answer. There is no negative concentrations.

X = <em>0.0385 atm</em> → Right answer.

Replacing for pressures in equilibrium:

N₂ = 0.790atm - X = <em>0.7515atm</em>

O₂ = 0.210atm - X = <em>0.1715atm</em>

NO = 2X = <em>0.0770atm</em>

3 0
3 years ago
Read 2 more answers
What is the place of metalloids in the periodic table?
sleet_krkn [62]
B,Si,Ge,As,Sb,Te, and At are all the metalloids on the periodic table of elements.

3 0
3 years ago
Which of the following would be an example of an amorphous solid?
sveticcg [70]

I think B. because of this picture??

3 0
3 years ago
How do I graph Charles's law equation?
Blizzard [7]

Answer:

we needa see the equations

3 0
3 years ago
A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container. Since Kr is expensive, you wish to re
Elena-2011 [213]

Answer:

a) 24.31 g

b) 16.69 g

Explanation:

A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.

After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.

Therefore, Pressure of Kr = 0.193 atm

Pressure of CO2  = 0.729 - 0.193 = 0.536 atm

Their mole fraction can be also determined as follows:

CO2 = \frac{Presssure due to CO_2}{Total pressure}

CO2 = \frac{0.536}{0.729}

= 0.735

Also; for Kr ; we have

Kr = \frac{0.193}{0.729}

Kr = 0.265

Molar mass of CO2 = 44 g/mol

Molar mass of Kr = 83.78 g/mol

Mass of CO2 = mole fraction * molar mass = 0.735 * 44 = 32.34

Mass of Kr = 0.265 *  83.78 = 22.20

Total mass = 32.34 +22.20 = 54.54

The Percentage of gas in mixture is  as follows:

% CO2 = \frac{32.34}{54.54}* 100 %

= 0.5930

= 59.30%  

(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g

% Kr =\frac{22.20}{ 54.54} * 100 %

= 0.407

= 40.70 %

(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g

4 0
3 years ago
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