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Paul [167]
3 years ago
15

When you hammer a nail, which types of energy are you using? Select all of the correct answers.

Chemistry
1 answer:
zhuklara [117]3 years ago
6 0

Answer:

U using kinetic energy

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The initial explanation for a phenomenon prior to experimentation is called a:
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The explanation for a phenomenon is a hypothesis something happened that you sure that was going to happen
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3 years ago
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If the hydrogen ion concentration, [H+], in a solution is 4.59 x 10-6 M, what is [OH-]?
atroni [7]

Answer:

2.18x10^-9 M

Explanation:

From the question given,

Hydrogen ion concentration, [H+] = 4.59x10^-6 M

Hydroxide ion, [OH-] =?

The hydroxide ion concentration, [OH-] in the solution can be obtained as follow:

[H+] x [OH-] = 1x10^-14

4.59x10^-6 x [OH-] = 1x10^-14

Divide both side by 4.59x10^-6

[OH-] = 1x10^-14 / 4.59x10^-6

[OH-] = 2.18x10^-9 M

6 0
3 years ago
One way to remove the pollutant nitrogen monoxide, NO, from mobile diesel exhaust is by reacting it with ammonia, NH, as seen in
SSSSS [86.1K]

Answer:

m_{NH_3}=21.6gNH_3

Explanation:

Hello there!

In this case, in agreement to the given chemical reaction, it is possible for us to calculate the mass of NH3 required to remove 57.0 g NO via the stoichiometry based off the 4:6 mole ratio between them:

m_{NH_3}=57.0g NO*\frac{1molNO}{30.01gNO}*\frac{4molNH_3}{6molNO}  *\frac{17.03gNH_3}{1molNH_3} \\\\m_{NH_3}=21.6gNH_3

Best regards!

6 0
3 years ago
The _______ often poses a conversion problem for pharmacy personnel, as most pharmacists consider it to be equal to 65 mg, but m
vichka [17]
The correct answer to the question that is being presented above would be 'one (1) grain'. The The <em>grain</em> often poses a conversion problem for pharmacy personnel, as most pharmacists consider it to be equal to 65 mg, but manufacturers consider it <span>equal to 60 mg.</span>
3 0
3 years ago
Calculate the pH of the resulting solution if 32.0 mL of 0.320 M HCl(aq) is added to (a) 42.0 mL of 0.320 M NaOH(aq). (b) 22.0 m
monitta

Answer:

a) pH = 11.5

b) pH= 3

Explanation:

a) lets calculate the number of moles of each reactant

moles of HCl = 32/1000 * 0.32 = 0.01024 mole

moles of NaOH = 42/1000 * 0.32 = 0.01344 moles

1 moles of HCl reacts with 1 moles of NaOH , so 0.01024 mole of HCl should react with 0.01024 moles of NaOH , but there is some excess NaOH.

excess NaOH= 0.01344 -0.01024 = 0.0032 moles

[H+]= \frac{10^{-14} }{0.0032} = 3.125 *10^{-12}

pH= -log [3.125*10^-12) = 11.5

b)  moles of NaOH = 0.00924

excess HCl present = 0.01024 - 0.00924 =.001

so excess [H+] = 0.001

pH= -log( 0.001) = 3

3 0
3 years ago
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