<span>6.6 degrees C
Let's model the student as a 125 w furnace that's been operating for 11 minutes. So
125 w * 11 min = 125 kg*m^2/s^3 * 11 min * 60 s/min = 82500 kg*m^2/s^2 = 82500 Joule
So the average kinetic energy increase of each gas molecule is
82500 J / 6.0x10^26 = 1.38x10^-22 J
Now the equation that relates kinetic energy to temperature is:
E = (3/2)Kb*Tk
E = average kinetic energy of the gas particles
Kb = Boltzmann constant (1.3806504Ă—10^-23 J/K)
Tk = Kinetic temperature in Kelvins
Notice the the energy level of the gas particles is linear with respect to temperature. So we don't care what the original temperature is, we just need to know by how much the average energy of the gas particles has increased by.
So let's substitute the known values and solve for Tk
E = (3/2)Kb*Tk
1.38x10^-22 J = (3/2)1.3806504Ă—10^-23 J/K * Tk
1.38x10^-22 J = 2.0709756x10^-23 J/K * Tk
6.64 K = Tk
Rounding to 2 significant digits gives 6.6K. So the temperature in the room will increase by 6.6 degrees K or 6.6 degrees C, or 11.9 degrees F.</span>
Answer:

Explanation:
As we know that the mass is revolving with constant angular speed in the circle of radius R
So we will have

now the position vector at a given time is

now the linear velocity is given as



Answer:
The magnetic field at a distance x = 5 m is 1.59 nT
Explanation:
Length of the wire, L = 2 cm = 0.02 m
Current, I = 20 A
x = 5 m
Magnetic field at a distance x = 5 m due to an infinitely long wire is given by:


To solve the problem it is necessary to apply the equations related to the conservation of both <em>kinetic of rolling objects</em> and potential energy and the moment of inertia.
The net height from the point where it begins to roll with an inclination of 30 degrees would be



In the case of Inertia would be given by

In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is



Replacing in Energy conservation Equation we have that
Potential Energy = Kinetic Energy of Rolling Object




Therefore the correct answer is C.
Answer:
A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.
Explanation:
Given that,
The mass of a ball, m = 2 kg
Kinetic energy of the ball, K = 25 J
We need to find the speed of the ball. The formula for the kinetic energy is given by :

So,
A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.