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2 years ago

A 2-kg ball is thrown at a speed of ____, exhibits 25j of kinetic energy.

Physics

1 answer:

bogdanovich [222]2 years ago

3 0

Answer:

A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.

Explanation:

Given that,

The mass of a ball, m = 2 kg

Kinetic energy of the ball, K = 25 J

We need to find the speed of the ball. The formula for the kinetic energy is given by :

$K=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 25}{2}} \\\\v=5\ m/s$

So,

A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.

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What is perfect machine?Why is this machine not possible in the real life?

andrezito [222]

Explanation:

The machine whose efficiency is 100% is known as perfect machine .This machine is not possible in real life because every machine is affected by the overcoming friction due to which is efficiency become less than hundred percent .

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2 years ago

A baseball thrown from the outfield to home plate does not have which of the following types of energy while it's in the air? A.

posledela

The ball does not have D. Radiant energy.

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2 years ago

A protein molecule in an electrophoresis gel has a negative charge.The exact charge depends on the pH of the solution, but 30 ex

Ad libitum [116K]

Answer:

The magnitude of the electric force on a protein with this charge is $7.2\times10^{-15}\ N$

Explanation:

Given that,

Electric field = 1500 N/C

Charge = 30 e

We need to calculate the magnitude of the electric force on a protein with this charge

Using formula of electrostatic force

$F=Eq$

Where, F = force

E = electric field

q = charge

Put the value into the formula

$F=1500\times30\times1.6\times10^{-19}$

$F=7.2\times10^{-15}\ N$

Hence, The magnitude of the electric force on a protein with this charge is $7.2\times10^{-15}\ N$

6 0

3 years ago

A photon has 3.4 × 10–18 joules of energy. Planck’s constant is 6.63 × 10–34 J•s.

hodyreva [135]

Ok i will answer for real this time. Please give me brainliest.
<span>The Answerr is:
5.12*10^15. Since e=h*f, f=e/h. 3.4*10^(-18)/h.
</span>i am so sorry i was doing a challenge and i needed answers to get 100 pts.
Hope I Helped
~TeenOlafLover <3

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2 years ago

At what distance will the weight of a body be halved , Earth's radius=6.4×10^6

Sholpan [36]

A body of mass m has weight

F = GMm/r²

on the surface of the Earth, where G is the universal gravitational constant, M is the mass of the Earth, and r is it's radius.

If the weight is to be halved, then we have

1/2 F = 1/2 GMm/r² = (1/√2)² GMm/r² = GMm/(√2 r²)

so the distance between the body and the planet's center needs to be

√2 × 6.4 × 10⁶ m ≈ 9.1 × 10⁶ m

5 0

2 years ago