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Nady [450]
3 years ago
12

Evaluate the expression of 8x - 20 if x=10

Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0

Answer:

60

Step-by-step explanation:

1. Substitute

8 (10) - 20

2. Multiply

80 - 20

3. Subtract

60

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the perimeter of a triangle is 12cm. which one of the following is not possible sides of a trianglr? a)1 b)5 c)6 d)none of thish
Phantasy [73]

Perimeter of triangle = 3(side)

P = 3(s)

12 = 3s

12/3 = s

4 = s

I think there is a typo in your post.

The question should be: WHICH ONE OF THE FOLLOWING IS A POSSIBLE SIDE OF THE TRIANGLE?

In that case, 4 cm is the answer. However, 4 cm is not listed among the choices. So, choice d is the answer.

7 0
4 years ago
I need help on this assignment
JulsSmile [24]

Given:

A figure of a rectangular prism with length l, width w and height h.

To find:

The surface area of the rectangular prism.

Solution:

The product of twice of the length l and the width w is:

2\times l\times w=2lw          ...(i)

The product of twice of the length l and the height is:

2\times l\times h=2lh           ...(ii)

The product of twice of the width w and the height h is:

2\times w\times h=2wh       ...(iii)

The surface area of the prism is the sum of (i), (ii) and (iii). So, the expression for the surface area is:

A=2lw+2lh+2wh

A=2(lw+lh+wh)

Therefore, the required expression is 2(lw+lh+wh).

5 0
3 years ago
4.
Svetlanka [38]

Step-by-step explanation:

si your trying to solve for c, or the hypotenuse? excuse me typing out a few things my keyboard is broken

4² plus 4²

16 plus 16 = 32

32 goes under the symbol

4 0
3 years ago
the cost in dollars, of making n birthday caked is represented by C= 24n +35. How many birthday cues are made when the cost is $
Debora [2.8K]

fifteen (15) birthday cues.

8 0
3 years ago
Find the midpoint of a line segment with given endpoints (4,-5) and (-6,3)
Mashcka [7]
The equation for the midpoint of a line segment is ( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}). Thus, the midpoint of this segment is (\frac{4 + (-6)}{2}, \frac{-5 + 3}{2}) = \boxed{(-1, -1)}.
3 0
4 years ago
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