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Ierofanga [76]
3 years ago
15

When are magnets attracted and when are they repelled.

Physics
1 answer:
vova2212 [387]3 years ago
3 0
Magnets are attracted when each of the different sides, most commonly known as "North" and "South", are facing each other. They repel when North and North, or South and South are facing each other.
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8/9 score.....................

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If I drop my egg unprotected, then it will break.
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All of the following are functions of the skeletal system EXCEPT:
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A cube of wood having an edge dimension of 20.0cm and a density of 650 kg /m³ floats on water. (a) What is the distance from the
Zarrin [17]

The distance from the horizontal top surface of the cube to the water level is "6.282 cm".

<h3>What is Archimedes' principle?</h3>

According to Archimedes' principle, the weight of the fluid that the body displaces is equal to the upward buoyant force that is applied to a body submerged in a fluid, whether fully or partially. The Archimedes' principle is a fundamental physical law in fluid mechanics. It was created by Syracuse's Archimedes.

According to Archimedes' principle, a body submerged in a fluid experiences an upward force proportional to the weight of the fluid that has been displaced. One of the prerequisites for equilibrium is this. We believe that the buoyancy force, also known as the centre of buoyancy, is situated in the middle of the submerged hull.

From Archimedes' principle, we get

\rightarrow L^3 \rho_{\text {Wood }} &=L^2 d \rho_{\text {Water }} \\

d &=L \frac{\rho_{\text {Waat }}}{\rho_{\text {Water }}} \\

&=18 \times \frac{651}{1000} \\

=11.72cm

So,

The distance from horizontal top to the water level will be:

=18-11.72

=6.282cm

To learn more about Archimedes' principle refer to:

brainly.com/question/1155674

#SPJ4

4 0
1 year ago
Cyclotrons are widely used in nuclear medicine for producing short-lived radioactive isotopes. These cyclotrons typically accele
lyudmila [28]

Answer:

Part a)

v = 3.16 \times 10^7 m/s

Part b)

r = 0.166 m

Explanation:

Part a)

As we know that the energy of the Hydride ion is given as

E = 5 MeV

here we have

\frac{1}{2}mv^2 = 5\times 10^6(1.6 \times 10^{-19})

also we know that

m = 1.6 \times 10^{-27} kg

now we have

v = \sqrt{\frac{2 \times 5 \times 10^6(1.6 \times 10^{-19}}{1.6\times 10^{-27}}

v = 3.16 \times 10^7 m/s

Part b)

As we know that magnetic force on the charge is centripetal force

so we have

qvB = \frac{mv^2}{r}

so we have

r = \frac{mv}{qB}

so we have

r = \frac{1.6 \times 10^{-27}(3.16 \times 10^7)}{(1.6 \times 10^{-19}) 1.9}

r = 0.166 m

4 0
3 years ago
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