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3 years ago

please hurry In which state of matter has the LEAST kinetic energy? A) gas B) liquid C) plasma D) solid

Physics

2 answers:

anastassius [24]3 years ago

7 0

Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy.

otez555 [7]3 years ago

4 0

The answer is d.
gas has molecules that are far apart, therefore having more room to move around, while solids have molecules close together that cannot move as easily.

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What is the formula for momentum? * p = m/v f = m x a f = m/s p = m x v

KiRa [710]

Answer:

momentum in a body can be calculated using

Momentum=Mass×Velosity 

ie(p=m×v)

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2 years ago

Approximately how many atoms are there along a 9.5 cm line

Troyanec [42]

First convert 5.5 cm to meters.

(5.5 cm / 1) x (m / 100 cm) = 0.055 m

A typical atom is about 1.0E-10 m in diameter; thus:

0.055 m / 1.0E-10 m = 5.5E8 atoms or 550,000,000 end-to-end atoms in 5.5 cm

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2 years ago

Ilya and Anya each can run at a speed of 7.30 mph and walk at a speed of 4.00 mph. They set off together on a route of length 5.

katrin [286]

Answer:

a)0.9675 h

b)5.168 mph

c)0.885 h

d)5.65 mph

Explanation:

The distance travelled by a moving object can be calculated as the velocity multiplied by the time, for this problem we can divide the problem in two stages, one where the are walking and another where they run,

Considering the total time for Anya is $t_{a}$ :

She first walks for half the distance (2.5 miles) so:

$2.5 miles=V_{w}*t_{a1}$

Solving for $t_{a1}$ :

$t_{a1}=\frac{2.5miles}{V_{w}}=\frac{2.5miles}{4 mph}=0.625 h$

Then she runs the other half of the distance:

$2.5 miles=V_{r}*t_{a2}$

$t_{a2}=\frac{2.5miles}{V_{r}}=\frac{2.5miles}{7.3 mph}=0.3425 h$

Adding this two durations we have the total time it takes for Anya to cover the distance:

$t_{a}=0.3425 h+0.625 h=0.9675 h$

The average velocity can be calculated as the total distance divided by the total time:

$V_{a-av} =\frac{5 miles}{0.9675 h} =5.168 mph$

Considering the total time for Ilya is $t_{I}$ :

She first walks for half the time so:

$d_{I1}=V_{w}*t_{I}/2$

Where $V_{w}$ is the velocity when walking (same for both people). On the second half she runs:

$d_{I2}=V_{r}*t_{I}/2$

This two distances must sum the total distance 5 miles, so:

$d_{I2}+d_{I2}=5 miles$

replacing the expressions above:

$V_{w}*t_{I}/2+V_{r}*t_{I}/2=(V_{w}+V_{r})*t_{I}/2=5 miles$

$t_{I}=\frac{5miles*2}{V_{w}+V_{r}}=\frac{10 miles}{4mph+7.3mph}=0.885 h$

so it takes Ilya 0.885 hours to to cover the distance

The average velocity can be calculated as the total distance divided by the total time:

$V_{I-av} =\frac{5 miles}{0.885 h} =5.65 mph$

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3 years ago

In a Millikan oil-drop experiment, the condenser plates are spaced 2.00 cm apart, the potential across the plates is 4000 V, the

astraxan [27]

Answer:

Answer is in the following attachment

Explanation:

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3 years ago

Two objects, A with charge +Q and B with charge +4Q, are separated by a distance r. The magnitude of the force exerted on the se

scZoUnD [109]

Answer:

The magnitude of electric force on object B due to object A when they are 2r distance apart is F/4.

Explanation:

Given :

Electric charge on object A = +Q

Electric charge on object B = +4Q

When the objects A and B are r distance apart, the magnitude of electrostatic force exerted on B due to A is given by the relation :

$F=\frac{1}{4\pi\epsilon_{0} } \frac{Q\times4Q}{r^{2} }$ .....(1)

Now, the two objects are apart by distance of 2r, hence the force acting on the object B due to A is :

$F_{1} =\frac{1}{4\pi\epsilon_{0} } \frac{Q\times4Q}{(2r)^{2} }$

$F_{1} =\frac{1}{4\pi\epsilon_{0} } \frac{Q\times4Q}{4r^{2} }$

Substitute equation (1) in the above equation.

$F_{1} =\frac{F}{4}$

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3 years ago